What is the logic used to obtain those numbers?
2006-07-16 17:01:40 · 10 answers · asked by Furaha 1 in Education & Reference ➔ Primary & Secondary Education
The answer is 50050 , 850850 & 16166150
50 x 7 = 350
350 x 11 = 3850
3850 x 13 = 50050
50050 x 17 = 850850
850850 x 19 =16166150
You just times the answer of previous answer with the continuing prime number.
2006-07-16 17:14:39 · answer #1 · answered by maxorian 3 · 0⤊ 0⤋
57750, 1097250,25235750
Multiply each number by 4 times more than the last number starting with 7. 50 times 7 is 350. 7 plus 4 is 11. 11 times 350 is 3850. 11 plus 4 is 15. 15 times 3850 is 57750. Then by 19 and finally by 23.
2006-07-16 17:10:25 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The answer is
50 x 7 = 350
350 x 11 = 3850
3850 x 15 = 57750
57750 x 19 = 1097250
1097250 x 23 =25236750
2006-07-16 17:23:19 · answer #3 · answered by Anonymous · 0⤊ 0⤋
50 x 7 = 350
350 x 11 = 3850
3850 x 13 = 50050
50050 x 17 = 850850
850850 x 19 =16166150
2006-07-17 00:33:30 · answer #4 · answered by ameer j 1 · 0⤊ 0⤋
The answer is 50050 , 850850 & 16166150
50 x 7 = 350
350 x 11 = 3850
3850 x 13 = 50050
50050 x 17 = 850850
850850 x 19 =16166150
You just times the answer of previous answer with the continuing prime number.
2006-07-17 01:44:51 · answer #5 · answered by JJ 4 · 0⤊ 0⤋
50 * 7 = 350
350 * 11 = 3850
3850 * 13 = 50050
50050 * 17 = 850850
850850 *19 =16166150
16166150 * 21
2006-07-16 18:14:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋
50 x 7 = 350
350 x 11 = 3850
3850 x 15 = 57750
2006-07-17 03:25:20 · answer #7 · answered by Anonymous · 0⤊ 0⤋
655
2006-07-17 02:47:04 · answer #8 · answered by sai g 1 · 0⤊ 0⤋
57750109725025236750
Number in the series is obtained by multiplying previous number by 7,11,15,19,23,.. with starting number as 50.
2006-07-17 07:24:23 · answer #9 · answered by Shrikant 1 · 0⤊ 0⤋
38850 388850 3888850
50 * 7 = 350
50 * 77 = 3850
50 * 777 = 38850
50 * 7777 = 388850
50 * 77777 = 3888850
is this right?
2006-07-17 02:15:54 · answer #10 · answered by anand 1 · 0⤊ 0⤋