2006-07-16 15:50:29 · 4 answers · asked by Ann 1 in Science & Mathematics ➔ Chemistry
If the balanced equation is,
CuO+H2>Cu+H2O deltaH:-130.5kJ
The for every 1 mole of CuO reacting with 1 mole of H2 gas, a change in enthalpy of -130.5 kJ occurs. If you double the amount of CuO reacting from 1 to 2, the one would double the change in enthalpy from the reaction.
If two moles of CuO reacts with 2 moles of H2, yielding 2 moles of Cu metal and 2 moles of water, then the resulting change in enthalpy would be -261 kJ.
2006-07-16 16:03:54 · answer #1 · answered by mrjeffy321 7 · 0⤊ 0⤋
double the delta H value!
2006-07-16 23:16:43 · answer #2 · answered by The Frontrunner 5 · 0⤊ 0⤋
Right as soon as I figure out what that is LMAO
2006-07-16 22:56:42 · answer #3 · answered by Paul G 5 · 0⤊ 0⤋
My partner is a chemical engineer, but I can't get him to do this! Darn. . .
2006-07-16 22:56:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋