4. What is the solution set of the equation n(to the 2nd) - n - 12= 0?
5. What is the solution set of the equation x(to the 2nd) - 9= 0?
6. What is the solution set of the equation x(to the 2nd)= 6x?
2006-07-16 12:32:56 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
4. n^2 - n - 12 = 0
You look for two consecutive factors that when added/subtracted, will give you -1 for the middle term and when multiplied together give you -12. In this case, you have -4 and +3.
Therefore,
(n-4) (n+3) = 0
You put both monomials equal to zero (since both multiplied together equals zero.
(n - 4) = 0 (n + 3) = 0
Solve it.
ANSWER: n = + 4 AND n = -3
#5. x^2 - 9 = 0
Since the middle term is 0, you need to find a number than when added/subtracted to itself, you get 0 (and when multiplied together equals 9). In this case, it is 3 and -3.
(x - 3) (x + 3) = 0
(x - 3) = 0 (x + 3) = 0
ANSWER: x = + 3 AND x = - 3
# 6. x^2 = 6x
In this case, the variable needs to be moved across the equals sign (so you subtract, in this case, 6x from both sides.
x^2 - 6x = 0
Since x is common in both numbers you can factor x out.
x (x - 6) = 0
Therefore, ANSWER: x = 0 AND x = + 6
Hope this helped!
2006-07-16 12:35:27 · answer #1 · answered by Obama, 47 y/o political virgin 5 · 1⤊ 0⤋
number 6 is 6
2006-07-16 19:37:25 · answer #2 · answered by jon 4 · 0⤊ 0⤋
Are you in Math 111?
2006-07-16 19:36:33 · answer #3 · answered by proud of it 4 · 0⤊ 0⤋
fqkf90 is the only one with the correct solutions.
2006-07-16 21:34:54 · answer #4 · answered by MsMath 7 · 0⤊ 0⤋
your first equation has no answer, given that you wrote it correctly. your second answer is 3, your 3rd answer is 6
2006-07-16 19:40:43 · answer #5 · answered by Ray H 2 · 0⤊ 0⤋
4. 4
5. 3
6. 6
Thank you.
2006-07-16 19:37:15 · answer #6 · answered by questionman 2 · 0⤊ 0⤋