What is the sum of all the numbers in the universe ?

Question

There is an exact value !!

Answer 1

Zero, since each positive number is eliminated by the same number with negative sign.

Answer 2

Symmetry is the key.
The sum of all the numbers in the universe is equal to number zero (0).
The universe we know is symmetrical if it is so then for every positive number (integer, real, or imaginary) there is a negative number. Then the sum of all positive numbers and their negative counterparts is equal to 0. For example
(…-3,-2,-1) + (1, 2, 3…)=0
Similarly for real numbers
(…-3.00,-2.99…) + (…2.99,3.00…)=0
So only one number represents the sum of all numbers in the universe and it is 0.

Answer 3

As "rt11guru" says, the answer is undefined.
Consider this infinite sum:
1 - 1+ 1 - 1 + 1 - 1 + 1 - 1 + ....
Add one and then subtract one, add one and then subtract one...
A person meay think that the answer is zero. If I group them like this, then I will get zero.
(1 - 1) + (1 - 1) + (1 - 1) + ...
But what if I decided to group them this way?
1 + (-1+1) + (-1+1) + (-1+1) + ...
then my sum will be one.
I could keep rearranging the ones and negative ones to get different sums. Therefore the sum does not exist.

Answer 4

I'm going to reword your question slightly because it's a little ambiguous in that it's not clear what "all the numbers in the universe" means. What is the sum of all the real numbers? As one of the previous answers states, that's undefined, but (thanks to Georg Cantor) we can talk about the cardinality (number of elements in) of the set of all real numbers. That's a "transfinite" number and is usually represented by the letter "c".

Answer 5

I here assume you are meaning positive integers. If you mean all numbers, both positive and negative, the answer is, of course, zero...

Infinity. Specifically, the infinite known as aleph null...

The answer, of course, is clearly limit (n -> infinity) Sum(i=0 to n) (i) which comes to n*(n+1)/2 which, in the limit, goes to simple infinity, aleph null.

You might check out Georg Cantor's work!

Answer 6

It's undefined.
Infinite sums are only defined in terms of the sequence of partial sums and it being convergent. Even adding just the integers, the sequence of partial sum would not converge. In order for the sequence of partial sums to converge, the nth term that you are summing has to go to zero. Not possible when the collection you are adding has an infinite number of terms of unlimited size.

Answer 7

The answer is zero if you are including both positive and negative numbers, because a positive plus a negative equals zero.
Example: -3 plus +3= 0

Answer 8

42

Answer 9

Well let's see. We'll add them up two at a time.

1 + (-1) = 0
2 + (-2) = 0

Ooops, better add the results of those two together before I forget.

0 + 0 = 0

3 + (-3) = 0
Aaah, better add that to my previous result before I forget it.

0 + 0 = 0

4 + (-4)= 0
mmmm, better add that to my previous result before I forget it.

0 + -326 = -326.

Wait, -326 wasn't my previous result. I think it was 73, or was it, uh, 1,048,575. Aagh, there's just too many numbers to add up.

Answer 10

ZERO

1 There are not really any numbers in the universe.They are just in our heads.

2 If you mean all the numbers, in our heads, they cover from zero to infinity in all directions and cancel each other out.

Answer 11

Zero