If my focus is given as (0, -3/2), how do I use that to find the standard equation of the parabola?

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If my focus is given as (0, -3/2), how do I use that to find the standard equation of the parabola?

I know the answer is x^2=-6y (or that is the given answer), but I need to know how they got it. Thanks.

PS, the vertex is 0,0. My professor didn't go over this at all and if I see one worked out I'm sure I can do the rest. TIA

2006-07-16 08:45:45 · 2 answers · asked by buttercup1137 2 in Science & Mathematics ➔ Mathematics

2 answers

Look here. It's got everything you should need to prove that.

http://en.wikipedia.org/wiki/Parabola

2006-07-16 08:53:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋

go to

http://en.wikipedia.org/wiki/parabola...

2006-07-16 16:17:07 · answer #2 · answered by vernon_j_m 2 · 0⤊ 0⤋