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12 answers

you know what i find funny? it's that peolpe just copy and paste the answer from wikipedia.org and they probably don't even understand 90% of the things that they give as an answer.

oh yeah
the answers 11.2Km/s

2006-07-16 05:41:38 · answer #1 · answered by Rajan 3 · 3 4

This velocity is known as escape velocity.

The escape velocity of Earth is 11.2 Km/Sec.

In physics, for a given gravitational field and a given position, the escape velocity is the minimum speed an object without propulsion, at that position, needs to have to move away indefinitely from the source of the field, as opposed to falling back or staying in an orbit within a bounded distance from the source. The object is assumed to be influenced by no forces except the gravitational field; in particular there is no propulsion, as by a rocket, there is no friction, as between the object and the Earth's atmosphere (these conditions correspond to freefall) and there is no gravitational radiation. This definition may need modification for the practical problem of two or more sources in some cases. In any case, the object is assumed to be a point with a mass that is negligible compared with that of the source of the field, usually an excellent approximation. It is commonly described as the speed needed to "break free" from a gravitational field.

One somewhat counterintuitive feature of escape velocity is that it is independent of direction, so that "velocity" is a misnomer; it is a scalar quantity and would more accurately be called "escape speed". The simplest way of deriving the formula for escape velocity is to use conservation of energy, thus: in order to escape, an object must have at least as much kinetic energy as the increase of potential energy required to move to infinite height.

Defined a bit more formally, "escape velocity" is the initial speed required to go from an initial point in a gravitational potential field to infinity with a residual velocity of zero, relative to the field. Conversely, an object starting at rest and at infinity, dropping towards the attracting mass, would reach its surface moving at the escape velocity. In common usage, the initial point is on the surface of a planet or moon. On the surface of the Earth the escape velocity is about 11.2 kilometres per second. However, at 9000 km altitude in "space", it is slightly less than 7.1 km/s.

The escape velocity from the surface of a rotating body depends on direction in which the escaping body travels. For example, as the Earth's rotational velocity is 465 m/s to the east at the equator, a rocket launched tangentially from the Earth's equator to the east requires an initial velocity of about 10.735 km/s relative to earth to escape whereas a rocket launched tangentially from the Earth's equator to the west requires an initial velocity of about 11.665 km/s relative to earth. The surface velocity decreases with the cosine of the geographic latitude, so space launch facilities are often located as close to the equator as feasible, e.g. the American Cape Canaveral in Florida and the European Centre Spatial Guyanais, only 5 degrees from the equator in Guyana.

For more Information see http://en.wikipedia.org/wiki/Escape_velocity

Hope you understand this.

2006-07-16 03:30:54 · answer #2 · answered by Sherlock Holmes 6 · 0 0

Escape velocity - as applied to ballistic motion - depends on an object's distance from Earth's center of mass.

V(escape) = (2G*M/r)^1/2

Where G is the gravitational constant
M is the mass of Earth (in this case)
And r is the initial distance from Earth's center of mass from which you are computing escape velocity.

Neglecting everything but Earth's gravity, an object launched ballistically from the surface would need to have an initial velocity of about 25,000 miles per hour, or about 11.2 kilometers per second, to continue moving away from Earth indefinitely.

2006-07-16 04:07:51 · answer #3 · answered by Ethan 3 · 0 0

There really is no velocity requirement. It is about thrust, not velocity. If there were enough sustainable thrust, the object could be moving as a snails pace, and still escape earth's gravity.

2006-07-16 03:11:55 · answer #4 · answered by Anonymous · 0 1

The earth's escape velocity is 6.96miles/sec or 11.2km/sec.

2006-07-16 03:16:01 · answer #5 · answered by Anonymous · 0 0

12 km per second.

2006-07-16 03:41:03 · answer #6 · answered by THE UNKNOWN 5 · 0 0

it is also known as escape velocity
it is 11.21km/sec. for earth

2006-07-16 03:14:12 · answer #7 · answered by new_einstein 2 · 0 0

7 miles a second (17,500 mph)

2006-07-16 03:12:40 · answer #8 · answered by Anonymous · 0 0

You should really ask Riley Martin, he will deffinately be able to help you. http://www.thecomingoftan.com/

2006-07-16 03:12:29 · answer #9 · answered by Anonymous · 0 0

11.2 km/sec

2006-07-16 03:20:41 · answer #10 · answered by lekhaj5 2 · 0 0

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