A number when multiplied by 7/18 instead of 7/8 and got the result
770 less than the actual result , find the original number?
2006-07-15 21:59:01 · 5 answers · asked by Stranger 1 in Science & Mathematics ➔ Mathematics
x*7/18+770=x*7/8
x=x*8/18+880
x*10/18=880
x=88*18
x=1,584
2006-07-15 22:07:39 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
1584
2006-07-16 08:19:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1980
2006-07-16 05:04:04 · answer #3 · answered by hemantha14 2 · 0⤊ 0⤋
x(7/8) - x(7/18) =770
x( (7/8) - (7/18) ) = 770
x( (126/144) - (56/144) ) = 770
x(70/144) = 770
x = 11*144
=1584
2006-07-16 17:39:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
our number is x ok.
x*(7/18)=x*(7/8)-770
770=x*(7/8)-x*(7/18)
=63x/72 - 28*/72
=35x/72
770*72=35x => x=1584
2006-07-16 05:06:57 · answer #5 · answered by jacob ecco 1 · 0⤊ 0⤋