A man travelled from 'a' to 'b' in 56 min,
if he traavelled the first 2/3 distance at a rate of 5Kmph, and the remaining diastance at 6Kmph, what is the total distance?
Try it please for me!
2006-07-15 21:24:53 · 6 answers · asked by Stranger 1 in Science & Mathematics ➔ Mathematics
Let x be the total distance. T1, the time for the first part of the trip is
{2/3)x/5 T2 for the second part is (1/3)x/6. These results will be in hours because the speeds are kph. 56 min is 56/60 hr so
(2/3)x/5 + (1/3)x/6 = 56/60.
Solve for x.
2006-07-15 21:33:21 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
let x be the total dis
man has travel 2x/3 distance in 5kmph. and x/3 dis in 6kmph.
time taken= (2x/3)/5+(x/3)/6=56/60
24x+10x=56*3
34x=56*3
x=56*3/34 in hours
2006-07-15 21:39:50 · answer #2 · answered by hemantha14 2 · 0⤊ 0⤋
the answer is:
4.94117647058823529411764705882353
tats the best i could do.
2006-07-16 01:28:35 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3.36 km
2006-07-15 21:43:44 · answer #4 · answered by Lutfor 3 · 0⤊ 0⤋
5.6 kms
2006-07-15 21:28:49 · answer #5 · answered by Cool Guy 2 · 0⤊ 0⤋
4.98kmph
2006-07-15 22:05:43 · answer #6 · answered by FILO 6 · 0⤊ 0⤋