English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1.A rocket ship is on its way to the moon at 15600 mi/h when it is alerted that a second ship is observed 1000 mi away (viewed at an angle 30o from the line of motion of the rocket ship). The second ship is traveling at 9000 mi/h and will cross the path of the first ship at right angles. Are they on collision path? If so how much time does the command pilot of the first rocket ship have to take evasive action?

2006-07-15 17:24:55 · 6 answers · asked by gen 2 in Science & Mathematics Physics

6 answers

I won't do it for you, but will give you a hint. This is a 30-60-90 right triangle, and the hypoteneuse is 1000 miles. The long leg (the first ship) is sqrt(3)/2 x 1000 = 500 sqrt(3) miles, and the short leg (the second ship) is 1/2 x 1000 = 500 miles.

Now you figure out how long it takes the first ship to cover its distance, and how long it takes the second ship to cover its. If the times are the same, they'll collide.

Of course, this problem ignores the fact that both ships are in gravitational fields, and neither is traveling in a straight line.

2006-07-15 17:41:17 · answer #1 · answered by bpiguy 7 · 0 0

Let's say Rocket 1 15600 mph and Rocket 2 9000 mph

If Rocket 1 sees Rocket 2 at 30 degrees and 1000 miles away then, we can draw a triangle between Rocket 1, Rocket 2 and the "point of collision" if any. One side of the triangle is the Rocket1-Rocket2 distance which is 1000 miles and, if you draw the triangle, you would see that is the largest.

So, you can take the cosine and see what is the distance between the Rocket2 and "the point of collision" and you would obtain around 866 miles.
So if the Rocket2 goes at 9000mph, it will reach the "collision point" in 0.096 hours.

But, in that time, the Rocket 1 moves 0.096 * 15600mph = 1501 miles.

The only thing we have to know is what was the distance between the Rocket1 and the "point of collision" (the last side of the triangle) and that is the sine (30) * 1000 miles= 500 miles.

So, when the Rocket2 crosses the path of the Rocket1, this is 1000 miles far away (it passed yet). It seems that there is not gonna be risk for the guys both in Rocket1 and Rocket2

2006-07-16 00:44:30 · answer #2 · answered by rflagg 2 · 0 0

No because the second rocket ship is traveling slower than the first (6600 mph slower) In 1/9th of an hour the second ship will cross the first's path(at a right angle) the 1st ship will have gone 1733.333.... in that time

2006-07-16 00:37:39 · answer #3 · answered by paulofhouston 6 · 0 0

thats a stupid high school text book questions why would their be more then one rocket ship flying around the moon any ways. i would say no the distance is to far for their to be any risk and besides they would have a comptuer that would tell them it doesnt make sense. so glad i graduated and dont have to put up with this kind of question any more

2006-07-16 00:31:05 · answer #4 · answered by ah64dtk 4 · 0 0

Still laughing..... ah64dtk made me smile

Thanks,
Buster

2006-07-16 00:46:27 · answer #5 · answered by Anonymous · 0 0

Is this homework?

2006-07-16 00:28:05 · answer #6 · answered by CLBH 3 · 0 0

fedest.com, questions and answers