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2006-07-15 06:15:00 · 5 answers · asked by Segun 2 in Science & Mathematics Chemistry

Pls give some explaination

2006-07-15 06:34:22 · update #1

5 answers

6.941 is an AVERAGE of weights. So if it's an AVERAGE the atomic weight GIVEN is CLOSER to 7 than 6. So, the answer would be Li-7.

2006-07-15 06:37:27 · answer #1 · answered by thewordofgodisjesus 5 · 0 0

There must be far more Li 7 than Li 6 if the atomic weight is much closer to 7 than it is to 6

Wikipedia says:

6Li 7.5% is stable with 3 neutrons
7Li 92.5% is stable with 4 neutrons

6Li content may be as low as 3.75% in
natural samples. 7Li would therefore
have a content of up to 96.25%.

Table of all Lithium isotopes:
isotope protons neutrons isotopic mass

Li-3 3 0 3.03078
Li-4 3 1 4.02719
Li-5 3 2 5.01254
Li-6 3 3 6.015122795
Li-7 3 4 7.01600455
Li-8 3 5 8.02248736
Li-9 3 6 9.0267895
Li-10 3 7 10.035481
Li-11 3 8 11.043798
Li-12 3 9 12.05378

2006-07-15 10:10:57 · answer #2 · answered by perseus 2 · 0 0

Li-7

2006-07-15 06:18:20 · answer #3 · answered by lk_musicz 1 · 0 0

An abundance ratio of 12.14±0.4 was obtained for Li7/Li6. On the basis of this ratio the masses of the two isotopes are 7.016±0.002 and 6.016±0.002 and the packing fractions are 23±3 and 26±3, respectively

2006-07-15 06:19:54 · answer #4 · answered by EST-A 2 · 0 0

relative atomic weight is given by

(a *weightA+b * weightB+ ... +z * weightZ)/(a+b+...+z)
where a, b, ...,z are the mole fractions of the isotopes A,B,...,Z
a+b+...+z=1
6.941=(a * 6+b * 7)/1
a+b=1
a=1-b
6.941=(1-b)*6+b*7
6.941=6-6b+7b
.941=b
a=1-b
a=0.059
so there is 94.1% Li7 and 5.9 *Li6 assuming no other isotopes

2006-07-15 08:59:29 · answer #5 · answered by zebbedee 4 · 0 0

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