simplify the following using the laws of exponents:-?

Question

2g square(g cube-g square+g-1)=

Answer 1

dude, its summer!

Answer 2

2g^5 - 2g^4 +2g^3 -2g^2
the law of exponent applied is multiplying exponential terms with the same base.

The law states that when we multiply factors having the same base, we simply copy the common base and then add their respective exponents. Furthermore, we also apply the ditributive property of mutiplication over addition to simplify the problem.

Answer 3

2g^2 (g^3 - g^2 + g - 1)

You "distribute" the 2g^2 into the polynomial:

[(2g^2 * g^3) - (2g^2 * g^2) + (2g^2 * g) - (2g^2 * 1)]

The law of exponents says when you multiply, say, x^2 and x^4, you add the exponents, x^2 * x^4 = x^6

So do the same with the "g's"
[(2g^(2+3)) - (2g^(2+2)) + (2g^(2+1)) - (2g^2)]
=2g^5 - 2g^4 + 2g^3 - 2g^2

Answer 4

using the distributive law and removing the brackets
=2g^5-2g^4+2g^3-2g

Answer 5

2g^2(g^3 - g^2 + g - 1) = 2g^5 - 2g^4 + 2g^3 - 2g^2

Answer 6

(2g^2)(g^3 - g^2 + g - 1)

(2 * g^(2 + 3)) - (2 * g^(2 + 2)) + (2 * g^(2 + 1)) - (2 * g^(2 + 0))

2g^5 - 2g^4 + 2g^3 + 2g^2

Answer 7

2g^5 - 2g^4+2g^3 - 2g^2

but I'm voting for the first answer

Answer 8

[2g^2][(g-1)^2][(g+1)]