Give 2 linear equations tangent to the function f(x) = 3x² + 5x + 7 and passes through (0,3)
^_^
2006-07-14 21:34:41 · 5 answers · asked by kevin! 5 in Science & Mathematics ➔ Mathematics
6x+5 = (3x^2 + 5x + 4)/x
6x^2 + 5x = 3x^2 + 5x + 4
3x^2 = 4
x = +/- 2sqrt(3)/3 (The x values of the tangency points)
Your equations are therefore:
y = (4sqrt(3)+5)x + 3
y = (-4sqrt(3)+5)x + 3
2006-07-14 22:45:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
X+3
6X+8
2006-07-15 05:20:33 · answer #2 · answered by Best Guy 1 · 0⤊ 0⤋
How about doing your own homework instead of being on the Internet.
2006-07-15 04:39:53 · answer #3 · answered by lyndell v 4 · 0⤊ 0⤋
f'(x) = 6x + 5
y-y1=m(x-x1)
=> y-3=m(x)
lets find m1 m2 by takin x=0,1
=> y-3=5x
y-3=11x
(wild guess, haha)
2006-07-15 06:00:35 · answer #4 · answered by xopix1 1 · 0⤊ 0⤋
Sorry- Im not up to trig.
2006-07-15 04:39:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋