t = time.
Suppose v(t) = v(0) + at. Then t = {v(t) - v(0)}/a
Suppose (distance d) = (constant speed v) x time. Then t = d/v
2006-07-14 19:06:43
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answer #1
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answered by Thermo 6
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it's all the same equation. (f=ma) is force = mass * acceleration. dv/dt is the derivative of velocity with respect to time which is equal to acceleration. d^2s/dt^2 is the second derivative of position which is acceleration (the first is velocity). It means if your problem gives you a function for position, take the derivative twice with respect to t and plug in the time in question to get force. If it gives you an equation for velocity take the dervative once and plug in t to get force.
2006-07-15 02:09:50
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answer #2
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answered by San 2
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t is dimensionless, so i think there could be no formula for t in classic physics.
but i know the average of time (TAU <= a greek alphabet) in measuring the current is: (TAU) = RC
R is the resistance and C is the capacity of the capacitor.
as i said t is dimensionless and does not depend on x. in this formula t only depends on two constant values (not variables)
but the definion of time is not yet completely underestood. read Quantum physics and relativity, to know more about time.
2006-07-15 02:31:22
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answer #3
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answered by ___ 4
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In terms of what do you want t?
you can have (from m=dv/dt) : dt = dv/m => integrate to get
t =(v2 - v1) /m
2006-07-15 02:09:27
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answer #4
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answered by Capt BloodLoss 2
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If you gonna ask a question like that, you could at the least clarify a bit more .
2006-07-15 02:02:25
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answer #5
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answered by IRunWithScissors 3
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f = ma for constant acceleration, or
f=m(v-v0)/(t)
so, t = f/(m(v-v0))
Jerk is the derivative of acceleation and I would suggest using differential equations to solve things with non-constant acceleration.
2006-07-15 02:31:25
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answer #6
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answered by Mark L 1
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t=v/a
2006-07-15 02:04:24
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answer #7
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answered by taureanboy90 3
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