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given the general form: A cos(bx+c)+ K
solve for phase shift and horizontal shift
phase shift is [- c/b] or bx+c = 0

I didn't chatch in class what is horizontal shift :-(

2006-07-14 16:57:39 · 7 answers · asked by BIGDAWG 4 in Science & Mathematics Mathematics

HURRAY! I found it in my handwritten class notes, thanks to everyone who answered me!!!!
it's pos or neg inverse of the c value

2006-07-14 19:56:21 · update #1

7 answers

I believe what is being asked for is a subtle difference in units. The phase shift relative to sin(bx) would be "c" in units of radians or degrees. This describes the shift of the waveform at x = 0 The phase shift can also be described in units of x because it causes a translation of the waveform on the x-axis. This translation is a horizontal shift. Both really are the same thing, but the measurement is given from a different perspective/units.

To find the phase shift in units of x (usually x is time, t):
Acos(bx) = non-shifted waveform. It has amplitude A at x = 0.
With a phase shift, what is x at the same amplitude of A?
Acos(bx + c) = A
cos(bx + c) = 1
bx + c = 0 (after taking inverse cosine)
x = -c/b (same formula you have).

Note that c is in units of radians or degrees, so -c/b is in units of x which is typically time, but in this case no one has said what units it is...so it is in general a horizontal shift.

Typically, one would say that the cosine wave has a phase of c radians, or is out of phase by c radians. If one were asked for the phase shift in radians, it would be c (not -c/b which is not in radians, but in units of x which is normally time). If one were asked for the phase shift in units of x, they would want to know the horizontal shift or movement translation of the waveform with the phase c versus the waveform 0 phase. This is the -c/b equation which is in units of x (time). I believe this is the horizontal shift asked for.

In other words, the phase shift itself is usually described in units of phase (radians or degrees) and so is conventionally just the value c in your equation because this is the phase that has been added to Acos(bx) to result in a phase shift. In most applications, the quantity bx would be wt or 2*pi*f*t and the units would become radians or degrees so c would also be in radians or degrees.

2006-07-14 17:31:16 · answer #1 · answered by SkyWayGuy 3 · 4 1

section shift and horizontal shift are distinct section shift, you both improve or decrease the era of the graph, a unique sin graph have a era of 2pi, somewhat shift can change that by technique of increasing the era or lowering it a horizontal shift, it purely strikes the completed graph left or top with out affecting the era

2016-12-06 12:19:03 · answer #2 · answered by ? 3 · 0 0

A is the AC (alternating current) amplitude
K is the DC (direct current) bias
c is the phase shift factor (horizontal shift)
b is the FM (frequency modulation) factor

2006-07-14 17:44:29 · answer #3 · answered by none2perdy 4 · 0 0

They're the same thing, as far as I know. When I taught trig, I asked my students to find the period, amplitude, phase shift, and vertical displacement.

2006-07-14 17:22:10 · answer #4 · answered by jenh42002 7 · 0 0

a horizonal shd is diagnol and a vertical is up and down on the y axis

2015-09-30 02:40:25 · answer #5 · answered by Megan 1 · 0 0

I beileve that they are the same thing

2006-07-14 17:43:27 · answer #6 · answered by Anonymous · 0 0

WTF lol

2006-07-14 17:01:51 · answer #7 · answered by DuhMan 2 · 0 0

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