It seems you're confused by video footage you've seen of NASA's KC 135-A (military variant of the Boeing 707), known as the "Vomit Comet".
From the website I've linked below :
"To simulate microgravity conditions, the plane ascended steeply, leveled off and began a dive. For 20 to 30 seconds people aboard the plane were able to experience weightlessness."
There' no such thing as a "degravitized room". Considering that we still don't know what gravity even *is* at this point, that sort of technology is far, far beyond us.
2006-07-14 18:04:24
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answer #1
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answered by M B 2
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Cat Lover has it! Most people don't realize the space shuttle is free falling. However, it falls at a rate that is slower than the speed of the rotation of the earth, so it stays on the same orbit. whewwww. Get down Cat Lover!!! Good Luck
2006-07-14 23:04:19
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answer #2
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answered by marks3kids 5
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We can NOT "degravitize" a room or anything else. We can do nothing more than offset the force of gravity with some other force. Throw a ball straight up and the downward force of gravity on the ball is overcome by the energy of the ball moving upward. Gravity is still there, just cancelled.
2006-07-14 22:38:42
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answer #3
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answered by Chug-a-Lug 7
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I've never heard of a degravitized room,I don't believe that's possible.As for gravity on the space shuttle,you could simulate gravity if you put it into a spin,but it would be real difficult to control.and even more difficult to get out of.
2006-07-14 22:41:42
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answer #4
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answered by foxspearman 4
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There is no such thing as "degravitizing."
When you are in orbit, you are basically in a state of continuous freefall. Because you are circling the earth fast enough to have your centripetal acceleration be equal to that of the acceleration of gravity.
If you jump off of something, you don't feel your weight because you are in free fall. That is all "weightlessness" is.
In order for them to have some sort of artificial gravity, the spaceship would have to be very long so they could spin it and then in the very ends of it they would have "gravity" due to centripetal force a = mv^2/r
2006-07-14 22:41:15
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answer #5
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answered by cat_lover 4
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Man, these kids have got to stop watching Fox TV and the Discovery Channel.
2006-07-15 03:48:46
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answer #6
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answered by Anonymous
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It wouldn't be very efficient to create a "gravitized" room in outer space. Besides, gravity cannot be created.
2006-07-14 22:40:21
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answer #7
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answered by Landon H 2
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Because it would require more energy than they want to bring along to power it.
2006-07-14 22:36:48
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answer #8
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answered by Anonymous
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degravitizer's day off
2006-07-14 22:37:05
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answer #9
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answered by Anonymous
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