which of the above; a box contains 2 red, 3 green and 5 yellow marbles, one marble is chosen. find the probability of choosing a green marble?
2006-07-14 13:46:15 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Common sense tells you it can't be 7/3, that's more than a 100% chance of something and that can't be.
You have 10 marbles, three of which are green. There is a 3/10 chance you will choose a green marble.
2006-07-14 13:50:40 · answer #1 · answered by jimbob 6 · 2⤊ 0⤋
3/10
2006-07-15 17:36:23 · answer #2 · answered by kittaaaay 2 · 0⤊ 0⤋
What is your sample space? There are 10 marbles, and each one represents one of 10 possible draws from the box. The sample space then has 10 elements.
Which items in your sample space are favorable, or constitutes "choosing a green marble"? There are 3 of them corresponding to the 3 green marbles.
So the probability is the size of the favorable event space divided by the size of the sample space: 3/10.
2006-07-14 23:33:11 · answer #3 · answered by alnitaka 4 · 0⤊ 0⤋
the probability of choosing a green marble is 3/10 (or 30%) but the ratio of choosing green is 3:7
2006-07-14 20:51:22 · answer #4 · answered by Anonymous · 1⤊ 0⤋
3/10
2006-07-14 20:50:06 · answer #5 · answered by akingsking 1 · 1⤊ 0⤋
3/10
2006-07-14 20:49:30 · answer #6 · answered by The R 2 · 1⤊ 0⤋
total no: of marbles = 2+3+5 = 10
no: of green marbles = 3
therefore P(Green) = 3/10
2006-07-14 21:07:09 · answer #7 · answered by chintu 2 · 1⤊ 0⤋
3/10.
2006-07-14 20:49:17 · answer #8 · answered by Hot T-Bone 4 · 1⤊ 0⤋
you know, there is a difference between asking for help on a problem, and asking for all of the answers.
You have about 20 math questions on here with other people answering them for you. These are not even difficult questions and yet you are too lazy to solve them.
You do realize that this is 6th MAYBE 7th grade level yes? It shouldn't require more then a few secconds of thought.
When did kids get to be so lazy?
2006-07-14 20:57:18 · answer #9 · answered by Aj 2 · 1⤊ 0⤋
take the derivative and set the equation equal to zero....that oughta help.
2006-07-14 20:51:03 · answer #10 · answered by Anonymous · 0⤊ 0⤋