Another monic polynomial. You're probably supposed to try a few examples to find out.
I assume this leading towards the theorem that when you factor a monic polynomial, all of the factors are monic polynomials?
2006-07-14 14:18:17
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answer #1
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answered by Bob G 6
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as a results of very fact of incontrovertible fact which you have not got any further gotten an answer yet, i'm going to coach out that Wolfram Alpha can a minimum of compute the minimum polynomial in question: x^6 + 3x^5 + 10x^4 + 15x^3 + 10x^2 + 3x + a million. Naively plugging in undesirable expressions for the roots in might desire to coach that the ratio is a root, and there are deterministic algorithms for proving the irreducibility of polynomials over Q, yet this could be a undesirable and backwards attitude.
2016-12-14 08:18:02
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answer #2
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answered by Erika 3
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take 3x and 5z^2, for instance. You get 15xz^2, another monic polynomial. That is because all the terms combine into one and you don't have to do messy FOIL or distribution.
2006-07-14 17:22:51
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answer #3
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answered by angyansheng65537 2
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Of course, another monic polynomial.
^_^
2006-07-14 21:23:23
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answer #4
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answered by kevin! 5
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take the derivative of the product and set equal to zero....that oughta sort things out for you.
2006-07-14 13:52:35
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answer #5
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answered by Anonymous
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