The Randolphs used 12 more gal of fuel oil in October
than in September and twice as much oil in November as in September. If they
used 132 gal for the 3 months, how much was used during each month?
2006-07-14 06:47:52 · 10 answers · asked by cupcake 1 in Education & Reference ➔ Homework Help
Oct=12xSept
Nov=2xSept
Sept,Oct,Nov=132gal
That's all I'm going to give you. Now go finish your homework!
2006-07-14 06:53:15 · answer #1 · answered by askme 4 · 0⤊ 0⤋
September is the base comparator, so let that be x. 12 gals more in Oct than in Sept means Oct = x + 12. Twice as much in Nov as in Sep means Nov = 2x. Therefore all three months are Sep, Oct, Nov or x + (x+12) + 2x and this we are told is 132 gals.
x + (x+12) + 2x = 132
2006-07-14 16:15:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Oct = Sept + 12
Nov = Sept x 2
132 = Sept + Oct + Nov
132 = Sept + (Sept +12) + (Sept x 2)
132 = 12 + (4 x Sept)
132 - 12 = 4 x Sepr
120/4 = Sept
30 = Sept
Therefore:
Sept used 30 gallons
Oct used 42 gallons
Nov used 60 gallons
2006-07-14 15:01:25 · answer #3 · answered by tressa1220 3 · 0⤊ 0⤋
Let X represent the # of gallons of fuel used in September.
X+(X+12)+2X=132
2006-07-14 13:56:31 · answer #4 · answered by Steve SS 1 · 0⤊ 0⤋
x = gallons used in September
x + x + 12 + 2x = 132
4x + 12 = 132
solve for x
2006-07-14 13:52:56 · answer #5 · answered by Jules 3 · 0⤊ 0⤋
Let X= September's usage.
October's usage = X+12
November's usage = 2X
therefore X+(X+12)+2X = 132
4X=120 ( or 132 - 12)
X = 30
Sept. = 30
Oct = 42
Nov. = 60
30+42+60 = 132
2006-07-14 13:58:31 · answer #6 · answered by Carlton73 5 · 0⤊ 0⤋
let x gallons used in september then in in october x+12
in november 2x
x+(x+12)+2x=132
4x+12=132
4x=132-12
4x=120
x=120/4=30
in sept= 30 gallons
in octo= 30+12= 42 gallons
in november= 2*30=60gallons
2006-07-14 16:31:39 · answer #7 · answered by flori 4 · 0⤊ 0⤋
Let x = the amount of fuel used in September
Let y = the amount of oil used in October
Let z = the amount of oil used in November
y=x+12
z=2x
x+y+z = 132
Plug in the values of y and z into the last equation to find x. Then use the x you found to find y and z.
2006-07-14 13:58:08 · answer #8 · answered by Charley 2 · 0⤊ 0⤋
s= Amount of oil in Sept.
Sept+ October + Nov = 132 gal
(12+S)+(s)+(2S)=132 so
3s+ (12+s) =132
when you figure out S, plug it back into the equation.
I think it works...
2006-07-14 13:54:21 · answer #9 · answered by wpililli 2 · 0⤊ 0⤋
(x+12)+(2x)=132
Solve for X to find September, then for each () for October and November.
2006-07-14 13:52:05 · answer #10 · answered by Robin J. Sky 4 · 0⤊ 0⤋