2331 words (in English translation)
The Piece of String by Guy de Maupassant
http://www.classicreader.com/read.php/sid.6/bookid.933/
In general, though, just about a centimetre shorter than you need it to be. Like, it's never bladdy long enuf, innit.*
(* I should have found this link for you earlier: http://www.urbandictionary.com/define.php?term=innit )
2006-07-14 03:20:09
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answer #1
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answered by Owlwings 7
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The question isn't how long is a peice of string, but how long is the entire length of the original string?
2006-07-14 03:19:58
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answer #2
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answered by stickyricky 3
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I'm sure I answered a question like this the other day....
I'll give you the same answer I gave them because I frankly can't be bothered to think of something witty and original.
A piece of string is as long as you want it to be! Or as long as it can get before you run out of string.
2006-07-14 03:18:24
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answer #3
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answered by Anonymous
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A piece is a length of 74mm string.
Going back to the Roman Times a coin the "Triens" had a hole in the middle of it with a piece of string through, the string was 74mm long or latin measurement "palmus" and most coins were commonly carried around the neck because they didn't have walletts.
although most think it is a rhetorical question the answer is in fact 74mm!!
10 points please x
2006-07-14 03:29:20
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answer #4
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answered by Anonymous
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It's twice as long as half a piece of string!
2006-07-14 03:21:48
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answer #5
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answered by Beckylou 3
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Infinate
2006-07-14 03:17:21
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answer #6
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answered by Nikki 4
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Twice half it's length! its an old one but not many people know that. Here's another one - two fish in a tank one says to the other "how do you drive this thing?"
2006-07-14 03:22:43
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answer #7
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answered by Phylofic Nod 1
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Double the length form its exact middle to one end
2006-07-14 03:18:44
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answer #8
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answered by Paul B 5
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whats the difference between a duck?(Smithy Bash st Kids)
2006-07-14 03:22:30
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answer #9
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answered by paintball puppy 2
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I think you'll find it is twice the distance from one end to the middle.
2006-07-14 03:18:34
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answer #10
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answered by Anonymous
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