its so easy.?

Question

factorize a ^ (n) + b ^ (n) and write the formula
in most simplest and general form
when n is an odd natural number.

no ......(dots) pls

Answer 1

Since you didn't specify what you want to factor it over, I'll factor it over the complex numbers:

Let k denote a primitive nth root of unity.

Then this factors as the product
(a+k*b)(a+k^2*b)(a+k^3*b)...(a+k^n*b)
which can be written in closed form using product notation as the following:

n
Pi (a+(k^i)*b)
i = 1

Answer 2

I cannot do math at all!
I hate it, wish I could figure out that problem!

Answer 3

one of the factors is (a+b) Try long division. You might get the following

(a+b) { a^(n-1) - a^(n-2)b +a^(n-3) b^2 - ...... + b^(n-1) }

check please