it is 0 since you get x-x in the product.
2006-07-13 18:27:36
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answer #1
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answered by raz 5
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4
2013-12-06 01:52:47
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answer #2
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answered by Harsha 1
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This Site Might Help You.
RE:
Can you simplify (x-a) (x-b) (x-c) ... (x-z)?
Can you simplify the algebraic multiplication shown above?
This is a quiz to test your reasoning powers. It's not something I need for homework.
Have fun.
2015-08-18 14:03:21
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answer #3
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answered by Tonita 1
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Answer will be 0.
Because as multipy (x-a) (x-b) (x-c) ... (x-z) we will come across (x-x) which will be equal to zero.
And any number multiplied by 0 will always give 0 as the product.
2006-07-13 19:15:44
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answer #4
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answered by Anonymous
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I'd recommend using symbolic algebraic manipulation software for solving this sort of problem. If that is not available I think that the Pascal's triangle method may work.
2006-07-13 18:23:43
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answer #5
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answered by insideoutsock 3
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x-x=0. So the product is 0
2006-07-13 18:33:14
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answer #6
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answered by Thermo 6
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Answer is 0
2006-07-13 19:10:38
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answer #7
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answered by vishvesh 1
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Don't agree. The reasoning for the answer is semantical, not mathematical.
The x on the left of each binomial is a variable. Each letter on the right of each binomial is a constant. The fact that one term looks like "x - x" doesn't mean it evaluates to zero.
2006-07-14 17:17:29
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answer #8
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answered by Anonymous
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E=Mc2 Ka-boom!
2006-07-13 18:15:58
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answer #9
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answered by Paul G 5
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looks like the expression is already factored into irreducible factors ....
x = a,b,c ... z
(the "zero's" of the expression )
"roots"
"answers"
2006-07-13 18:26:30
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answer #10
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answered by atheistforthebirthofjesus 6
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