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Can you simplify the algebraic multiplication shown above?
This is a quiz to test your reasoning powers. It's not something I need for homework.
Have fun.

2006-07-13 18:11:12 · 13 answers · asked by actuator 5 in Science & Mathematics Mathematics

13 answers

it is 0 since you get x-x in the product.

2006-07-13 18:27:36 · answer #1 · answered by raz 5 · 9 1

4

2013-12-06 01:52:47 · answer #2 · answered by Harsha 1 · 0 0

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RE:
Can you simplify (x-a) (x-b) (x-c) ... (x-z)?
Can you simplify the algebraic multiplication shown above?
This is a quiz to test your reasoning powers. It's not something I need for homework.
Have fun.

2015-08-18 14:03:21 · answer #3 · answered by Tonita 1 · 0 0

Answer will be 0.
Because as multipy (x-a) (x-b) (x-c) ... (x-z) we will come across (x-x) which will be equal to zero.
And any number multiplied by 0 will always give 0 as the product.

2006-07-13 19:15:44 · answer #4 · answered by Anonymous · 1 0

I'd recommend using symbolic algebraic manipulation software for solving this sort of problem. If that is not available I think that the Pascal's triangle method may work.

2006-07-13 18:23:43 · answer #5 · answered by insideoutsock 3 · 0 0

x-x=0. So the product is 0

2006-07-13 18:33:14 · answer #6 · answered by Thermo 6 · 0 0

Answer is 0

2006-07-13 19:10:38 · answer #7 · answered by vishvesh 1 · 0 0

Don't agree. The reasoning for the answer is semantical, not mathematical.

The x on the left of each binomial is a variable. Each letter on the right of each binomial is a constant. The fact that one term looks like "x - x" doesn't mean it evaluates to zero.

2006-07-14 17:17:29 · answer #8 · answered by Anonymous · 2 3

E=Mc2 Ka-boom!

2006-07-13 18:15:58 · answer #9 · answered by Paul G 5 · 0 3

looks like the expression is already factored into irreducible factors ....

x = a,b,c ... z

(the "zero's" of the expression )

"roots"
"answers"

2006-07-13 18:26:30 · answer #10 · answered by atheistforthebirthofjesus 6 · 0 0

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