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12 answers

mmmm....check a globe

2006-07-13 15:12:34 · answer #1 · answered by Anonymous · 0 1

You should remember your 30-60-90 triangles... Any equilateral can be split into 2 30-60-90 triangles. One of thir sides is the altitude, the other is a side, and the last is half a side. So, using the pythagorean theorem,
altitude^2 + (s/2)^2 = s^2
altitude^2 = s^2 - s^2/4 = 3s^2/4
altitude = s*sqrt(3)/2

2006-07-13 15:24:14 · answer #2 · answered by vishalarul 2 · 0 0

OK, pick a side. You'll notice that the altitude will go from the center of that side up to the corner. AH, now we have a right triangle. The hypotenuse has length s, and the one leg (the shorter one, by the way) has length s/2.

s^2 = (s/2)^2 + a^2 for a our altitude.

SO! a^2 = s^2 * (1-1/4)

OR, a = sqrt(3)*s/2 for sqrt the square root function

That means a = ~ 0.866*s give or take a bit

2006-07-13 15:18:58 · answer #3 · answered by gandalf 4 · 2 0

let altitude be X. Since it is an equilateral triangle all sides are equal = S. Hence Hypotenuse = S, Base = S/2. ( Because altitude of an equilateral triangle divides base equally)

Now use the formula which I am sure you know ...

hypotenuse square = altitude square + base square

2006-07-13 15:15:33 · answer #4 · answered by Billy Talent 3 · 0 0

Easy. Draw a line down from the vertex, perpendicular to the base. you have formed 2 triangles with a base of 8cm and a hypoteneuse of 16cm. 16 square minus 8 square will equal the altitude squared. 256-64 = 192 answer:square root of 192

2016-03-27 04:27:30 · answer #5 · answered by Anonymous · 0 0

If you have to calculate the area of a triangle and are not given the height to use the traditional formula 1/2bh, you can determine the height by the formula by knowing the angle of the base (being equilateral, that is a known 60degrees) valued as "B",

Find the sine of B, is equal to the side divided by the height.
sinB=s/h or h=s/sinB

Just takes a little trigonometry. :-)

2006-07-13 15:30:32 · answer #6 · answered by Juju_Bee 2 · 0 0

let altitude be x units. for equilateral triangle altitude is also median. thus it divides its base in half.thus length of half base is s/2 units. by applying pythagoras theorem to triangle formed by altitude on either its right or left side, equation is:
(s)square=(s/2)square + (x)square
solving, u get x=1.73s/2

2006-07-13 16:19:56 · answer #7 · answered by rum_fun 2 · 0 0

It will be
1/2*square root of 3*S
fore example if sides are =4,
then altitude will be square root of 12
(use Pythagoras theorem)

2006-07-13 15:21:15 · answer #8 · answered by HeavyRain 4 · 1 0

it is by using the Great Pythagorus theorem.
let a be altiitude then,
s*s = (s/2)*(s/2) + a*a
solvin this u will get the answer.
a=sqrt(3)/2 times s

2006-07-13 19:17:27 · answer #9 · answered by vishvesh 1 · 0 0

the height of an eq triangle is s/2 x radical3

2006-07-13 15:45:15 · answer #10 · answered by john m 2 · 0 0

h = (s * sqrt(3))/2

2006-07-14 02:32:37 · answer #11 · answered by Sherman81 6 · 0 0

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