if two people choose a number between 1-7, what is the probability that they will choose the same number?

Answer 1

1:49 For any given number there is a 1:7 chance that either person will pick it. So for both people to pick it, the probability is 1/7 x 1/7 or 1/49.

Answer 2

1 in 7

Answer 3

In the experiment of choosing a number between 1-7.
Total no of possible choices = number of ways in which one number can be choosen from total of 7 numbers

==> n = 7C1
==> n = 7 (either 1,2,3,4,5,6,7)

Let 'A' be the event of choosing a number by a first person.

Let 'B' be the event of choosing a number by a second person.

For event 'A'
----------------
Numbr of favourable choices = Numbe of chaces for first person for choosing one number
==> m = 1

For event 'B'
----------------
Numbr of favourable choices = Numbe of chaces for second person for choosing one number
==> m = 1

Probability of occurance of an event = No of favourable choices / Total no of possible choices

Therefore

P(A) = m/n
P(A) = 1/7

P(B) = m/n
P(B) = 1/7

Here both events are independent i.e the number choosen by the second person is not depends upon the number choosen by the first person.

Therefore
P(A intersectionB) = P(A) x P(B)
= 1/7 x 1/7
=1 / 49

:. The probability of the two persons will choose the same numbe r is 1/49.

For more detailes and better understanding:

http://www.futureaccountant.com/probability/

http://www.schoolingkids.com/probability/

Answer 4

One out of seven. Each number has a one in seven chance of being selected, let's say the first person chose #1...that fact has no impact on the second person's selection, so that is again one in seven.

Answer 5

1 in 98?

Answer 6

1 in 7

They both pick a number. So one has to match the other. That's the only thing that is needed.

Answer 7

A one out of seven chance.

Answer 8

RAC's answer is correct 1:49.

Answer 9

50 - 50.