solve 2/k=3/-5!=(not equalsto)5/7?

Answer 1

sory but - 5! donot exist..but 5! exist

Answer 2

As I explain to my students, the KEY to solving algebra problems is to:
(1) isolate the unknown variable and get it all by itself on one side of the equal sign,

(2) do the exact opposite of what's being done to the unknown variable right now.

In order to get K all by itself, you'll have to multiply both sides by it. This would give you K x 2/K = K x 3/-5, which leaves you with 2 = K x 3/-5.

Now we need to get K all by itself on the right. Well, we're multiplying it by 3/-5 right now, so we'd do the opposite, which is divide by 3/-5.

Doing that would give you 2 divided by 3/-5 = K.

To divide 2 by 3/-5, you need to flip the 3/-5 making it -5/3, and then multiply it by 2. This would give you -10/3, which is -3 1/3 (- 3 and a third).

Answer 3

Actually, this equation will always be true as long as k equals -80, because 3/-5! definitely does not equal 5/7.

What do those other answers mean... In this case, I have no idea what your equation is.

Answer 4

k=-10/3 and k!=(not equals)5/7

Answer 5

k is not equal to 14/5

Answer 6

2/k=3/-5
k/2=-5/3
k=-10/3
2/k is not equal to 5/7
k/2 is not equal to 7/5
k is not equal to 14/5

Answer 7

CrzyHarryPotter is right it's k= -10/3

Answer 8

k = -10/3, if the exclamation point is just randomally there, and not a factorial. otherwise, if it means factorial, it is not possible

Answer 9

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Answer 10

E=MC2