Two boxes are labelled "A" and "B". A sign on box A says "The sign on box B is true and the gold is in box A". A sign on box B says "The sign on box A is false and the gold is in box A". Assuming there is gold in one of the boxes, which box contains the gold?
2006-07-13 05:00:20 · 12 answers · asked by Raymond OConnor 2 in Science & Mathematics ➔ Physics
check ur iq here...
http://www.highiqsociety.org
and it doesnt ask such stupid twisters
and by the way..im a member there
2006-07-13 07:00:03 · answer #1 · answered by Prakash 4 · 0⤊ 0⤋
The message on a box could be partially false for the sign to be false as a whole. For the logical statement "A and B" to be false we need "either not A or not B".
There are 4 logical scenarios for the signs
A true B false
A true B true
A false B false
A false B true
with A true, all elements of the statement must be true, but because of A's statement: "sign B is true" we have a contradiction if both A and B are true or A is true and B is false.
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In Sign A false, then either the statement that "B is true" is in fact false or "gold in A" is false. Because both signs say "gold in A" and at least one must be true in this scenario, we can eliminate that statement and must focus on the truth of the signs statement. But we run into a contradiction here as well.
The only scenario which does not lead to a contradiction is when both sign A is false and sign B is false
sign A is false under both statements because the gold is not in A and Sign B is false. Sign B is false because the statement “gold in A” is false (although the other "sign A is false" is true). If one of the elements of an "and" statement is false then the entire statement is false.
Not only is the gold under box B, but both signs are false.
and my IQ is 142
2006-07-13 05:30:04 · answer #2 · answered by Discipulo legis, quis cogitat? 6 · 0⤊ 0⤋
The gold would be in box B.
If A says B is true and the Gold is in box A,
and B says A is false and the gold is in box A,
A states that B is true, but B states that A is false therfore B is not true so the gold must be in box B. Damn that's a thinker of a question.
2006-07-13 05:06:53 · answer #3 · answered by Thrasher 5 · 0⤊ 0⤋
There's a incoherence, because both signs say gold in box A. Sign B says sign A is false, but in that case sign B is false too b/c it also claims the gold is in A. So if both signs are false gold must be in B
2006-07-13 05:13:28 · answer #4 · answered by Atomin 5 · 0⤊ 0⤋
Gold is in box A. Sign B is true.
2006-07-13 05:03:25 · answer #5 · answered by Lupin IV 6 · 0⤊ 0⤋
The gold is in box B.
If B is true, the gold cannot be in box A
If A is false the gold cannot be in box A
That means the gold must be in box B
2006-07-13 06:00:19 · answer #6 · answered by physandchemteach 7 · 0⤊ 0⤋
Box B
2006-07-13 05:09:22 · answer #7 · answered by megh13 4 · 0⤊ 0⤋
It cannot be answered with the information given.
They are contradicting eachother and you cannot trust either sign. Sign A says that Sign B is true, but Sign B tells us that A is false. Neither is right and there is no answer.
2006-07-13 05:11:30 · answer #8 · answered by Chase T 2 · 0⤊ 0⤋
My IQ is one greater than the maximum of
everyone else's answer.
2006-07-13 05:02:58 · answer #9 · answered by PoohP 4 · 0⤊ 0⤋
What? Why are you always asking these questions?
2006-07-13 06:16:26 · answer #10 · answered by Writer 2 · 0⤊ 0⤋