A 4.0-kg object is moving across a friction-free surface with a constant velocity of 2 m/s. Which one of the following horizontal forces is necessary to maintain this state of motion?
a. 0 N
b. 0.5 N
c. 2.0 N
d. 8.0 N
e. depends on the speed.
2006-07-13 04:12:27 · 9 answers · asked by A.j. 3 in Education & Reference ➔ Trivia
Well, assuming that your surface is perfectly horizontal, then zero is your answer. There's no energy lost in that system, so you don't need to put any more energy.
But if you're on a slope and you want to maintain constant velocity, that's a different story...
2006-07-13 04:17:18 · answer #1 · answered by jkinla 2 · 2⤊ 0⤋
A. 0 N.
2006-07-15 21:13:39 · answer #2 · answered by Ken W 3 · 0⤊ 0⤋
It is 0 N.
F=ma if the velocity is constant ,means a=0
So F= m x 0, F=0
2006-07-13 04:18:32 · answer #3 · answered by Leprechaun 6 · 0⤊ 0⤋
incorrect. the mass of the guy ought to stay an same any the position in the universe. u say he's pulled with the stress of one hundred newtons so he acceleration on the moon should be one hundred/60= 10/6=5/3=a million-66m/s*2 which is going out to be just about a million/6 of earths acceleration.
2016-11-01 23:52:01 · answer #4 · answered by Anonymous · 0⤊ 0⤋
E=Mc^2
2006-07-13 16:35:03 · answer #5 · answered by thatonegirl 3 · 0⤊ 0⤋
0 N according to newton's 1st law of motion
2006-07-13 04:17:04 · answer #6 · answered by She Who Must Not Be Named 2 · 0⤊ 0⤋
Depends on atmosphere and its related friction.
2006-07-13 04:15:41 · answer #7 · answered by scruffy 5 · 0⤊ 0⤋
of course it is a because a body in motion with no forces stays in that motion.
2006-07-13 04:16:05 · answer #8 · answered by BonesofaTeacher 7 · 0⤊ 0⤋
a. neglecting the atmospheric friction
2006-07-13 04:16:54 · answer #9 · answered by helixburger 6 · 0⤊ 0⤋