2006-07-13 04:08:39 · 5 answers · asked by allysweets02 1 in Education & Reference ➔ Higher Education (University +)
Ok, the 'A' mean AVERAGE, itz not a variable people.
ATC = TC/Q
AFC = FC/Q
AVC = VC/Q
TC:Total Costs
FC: Fixed Costs
VC: Variable Costs
Q: Quantity
If TC = FC + VC, then TC/Q = FC/Q + VC/Q
I see your studying economics first year uni? or maybe last year of high school?
2006-07-13 04:15:00 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You multiplied both sides by A.
TC=FC+VC
A(TC)=A(FC+VC)
ATC = AFC + AVC
look for the "missing piece" in the first one, and see how the beginning and the end are related. Math is all about how things are related and describing the relationships.
But, that's the way I would look at it. Your teacher probably wants you to work backward in your proof, so-
ATC = AFC + AVC
A(TC)=A(FC+VC)
factor out A (undoing the distribution)
A(TC)/A=A(FC+VC)/A
divide both sides by A
TC=FC+VC
the A's cancel
2006-07-13 11:14:18 · answer #2 · answered by teachingazteca 3 · 0⤊ 0⤋
Hmm, I can't recall off the top of my head which axiom this one is, but let's try this:
AFC + AVC = A (FC + VC)
Thus = A (TC) per what is give.
ATC = A (TC) which is true by the Reflexive property.
2006-07-13 11:13:22 · answer #3 · answered by Jeff A 3 · 0⤊ 0⤋
Multiply with A on both sides then you will get the result you desire
2006-07-13 11:11:28 · answer #4 · answered by Sherlock Holmes 6 · 0⤊ 0⤋
To make your proof as formal as possible, make sure to list all the axioms you used as well.
2006-07-13 11:16:30 · answer #5 · answered by Paul from NYC 3 · 0⤊ 0⤋