54 - 4, 14, 24, 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 54.
P.S. I was first, guys!
2006-07-13 02:32:53
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answer #1
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answered by savagescorpio 3
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If you are explaining it correctly it should be 64. That is the first row of numbers 1 - 10 contain one 4. 11 - 20 contain another 4 this continues untill you get to the 40's which contain 9 fours, one in each number. However, you didn't specify if 44 is counted twice but I'm assuming it is once since you are saying that a number contain a digit 4 not digits. Therefore you keep counting and 64 is the last number totaling 15 numbers containing the digit 4.
2006-07-13 02:38:26
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answer #2
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answered by Anonymous
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She numbered 54 pages, as you already mentioned that 15 pages have the number 4
4, 14, 24, 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, and 54 being the last page.
2006-07-13 02:37:39
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answer #3
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answered by Anonymous
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49 pages.
Here's how:
The digit 4 has occurred 15 times. It occurs on the following page nos. : 4, 14, 24, 34, 40, 41, 42, 43, 44 (twice 4 !!), 45, 46, 47, 48, 49. Also, as the last page is 49, it contains the digit 4.
2006-07-13 02:33:23
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answer #4
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answered by prasannadatta 2
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54
the page numbers are - 4, 14, 24, 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 54
thats 15 pages with the digit 4 in it
2006-07-13 02:35:29
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answer #5
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answered by Suraj 3
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54 is the answer - the pages would be 4, 14, 24, 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 54
2006-07-13 02:35:50
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answer #6
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answered by tg 4
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54, pages are: 4, 14, 24, 34, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, and finally 54
2006-07-13 02:33:08
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answer #7
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answered by alienz67 3
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54 page numbers with 27 pages of paper
2006-07-13 02:37:48
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answer #8
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answered by Justin K 4
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54
2006-07-13 07:19:03
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answer #9
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answered by ACE 2
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54
2006-07-13 06:25:15
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answer #10
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answered by Anonymous
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