I know a number and want to find six numbers from 1 to 49 which adds to that particular no.?

Answer 1

As long as your answer is between 21 (1+2+3+4+5+6) and 279 (44+45+46+47+48+49) this should be easy to accomplish.

Let's say your number was 153. I would first divide this by 6. That gets you 25.5, so that tells me that the average of the six numbers should be 25.5. So I would pick 23, 24, 25, 26, 27, 28... add these up and you get 153.

Let's say you wanted to add to 154. That would be an average of 25.6666. Again I try 23, 24, 25, 26, 27, 28 but we already know that we get 153. So I just swap out the 28 for a 29 and I have 23, 24, 25, 26, 27, 29 for a total of 154.

Of if I wanted 152 (avg. = 25.3333)... We know 23, 24, 25, 26, 27, 28 doesn't work, but I can swap the lower number with 22, to get 22, 24, 25, 26, 27, 28.

150 would be 20, 24, 25, 26, 27, 28
151 would be 21, 24, 25, 26, 27, 28
155 would be 23, 24, 25, 26, 27, 30
156 would be 23, 24, 25, 26, 27, 31

If you list your particular number I could help you further, but I think you can do it on your own. Also, it isn't mandatory that the balls be consecutive, since there are lots of other ways to do this. For example you can swap a 26/27 pair with anything that adds to 53 (say 5 and 48)...

Except for certain sums, there should be multiple ways to pick the 6 numbers that add to a particular number.

Answer 2

i guess you pick to %. determination for a lottery sport, is that it? good success chum. yet right it truly is a thanks to play the strange: Factorial 40 9,factorial 40 8,factorial 40 seven and so on..... to factorial a million divided by technique of factorial 6,5,4,....a million. the end result? 13millions 890 thousand 436. those are your odds of triumphing 6 out of 40 9. bypass parent which # matches you ideal. As for me, i love 9. it truly is my luckiest # because the great issues in my existence has an association with 9.

Answer 3

hey,
try 2 make the qn more specific

Answer 4

What exactly is your question?