least common multiple?

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least common multiple?

4x^2y^3 and 5x^2y^3

2006-07-12 18:04:22 · 3 answers · asked by investing1987 3 in Education & Reference ➔ Homework Help

3 answers

Answer: X^2Y^3
Since
4(X^2Y^3)=4X^2Y^3
5(X^2Y^3)=5X^2Y^3

2006-07-12 19:27:34 · answer #1 · answered by judy 3 · 0⤊ 2⤋

20x^2y^3. This one looks confusing because of the x sqared and y cubed terms. Since both terms have the same x^2 and y^3 terms, think of it as a simpler question: what is the least common multiple of 4z and 5z. In this case we have made z equal to x^2 y^3. It really is just a matter of finding the least common multiple of 4 and 5, which turns out to be twenty.

2006-07-13 01:17:55 · answer #2 · answered by Anonymous · 0⤊ 0⤋

20x^2y^3

2006-07-13 01:09:02 · answer #3 · answered by schleppin 3 · 0⤊ 0⤋