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2/x+5 + x+23/x^2+x-20

2006-07-12 17:44:00 · 4 answers · asked by investing1987 3 in Education & Reference Homework Help

4 answers

you aren't lost... your still there..

2006-07-12 21:21:30 · answer #1 · answered by Anonymous · 1 0

=(2/x+5+x+23/x^2+x-20)^X^2
=2x+5x^2+X^3+23+X^3-20X^2
=15X^2+2X+2x^3+23
=2X^3-15X^2+2X+23 Answer

2006-07-13 00:56:55 · answer #2 · answered by judy 3 · 0 0

5x^2+2x^3+7

i multiplied the whole problem by x^2...try it. but yeah its like ALG2 right

2006-07-13 00:49:15 · answer #3 · answered by Nausea is annoying!!! 3 · 0 0

2/x+23/x^2+2x-15
2x+23+2x^2-15x^2
2x+23-13x^2
13x^2-2x-23
then u can factorize it

2006-07-13 00:54:52 · answer #4 · answered by fzaa3's lover 4 · 0 0

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