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Why is it necessary to calibrate the thermameter for the freezing point determination but not for boiling point determination? Thanks!

2006-07-12 15:12:12 · 7 answers · asked by Mike 1 in Science & Mathematics Chemistry

7 answers

Technically, you should perform both tasks due to the expansivity or glass and Hg or the substance in the thermometer e.g alcohol thermometer...

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2006-07-12 17:04:57 · answer #1 · answered by Aldebaran 2 · 0 0

freezing point is a little more constant because it is not nearly as pressure dependant. At low pressure the temperature at which water and any other substance changes sometimes by a large amount. Freezing is about the same unless the pressure is a large difference. Now if you are measuring the change in these two things it really does not matter what the thermometer calibrates at and so just read it the change should be correct.

2006-07-12 16:58:41 · answer #2 · answered by NVHSChemGuy 2 · 0 0

Calibrating a thermometer for freezing point determination is a lot easlier using freezing point. as ice melts at 0 C all you do is place ice compacted into a funnel stuck your thermometer in it and then the ice is melting you have your zero C points.

For boiling pt you have to mess with boiling water, boiling water will have localised hot points although stream is meant to be 100 C getting it dense enough so that the normal air does not affect the reading is quite hard.

2006-07-12 15:19:19 · answer #3 · answered by Mr Hex Vision 7 · 0 0

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2016-12-01 04:28:21 · answer #4 · answered by dahle 3 · 0 0

it's easier and once you have it calibrated for the melting point, you have it calibrated for the boiling point anyway. water boils at 100 C, but it does bubble and steam before that point, making it tougher to figure out exactly where it actually boils.

2006-07-12 15:45:40 · answer #5 · answered by The Frontrunner 5 · 0 0

If you are not confident in the integrity, precision, and accuracy of your thermometer, it is in your best interest to calibrate it to 0, but make sure that 100 degrees will read as such.

2006-07-12 15:50:03 · answer #6 · answered by M 4 · 0 0

If you don't do the boiling point, you don't have to apply the stem correction.

2006-07-12 17:53:30 · answer #7 · answered by rb42redsuns 6 · 0 0

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