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Solve this: 3 people went to a restaurant. After having the meal, they asked for the bill and the waiter brought them a bill of US$ 25 (long time ago -- food was cheaper). Each one gave the waiter a $10 bill. The waiter returned them 5 $1 bills. Each of the 3 people took one $1 bill and they left $2 on the table for the tip.

In summary: Each one paid $9. 3 times $9 equals $27. So, $27, plus $2, left as a tip, makes it $29. It's still $1 short for $30. Where did this $1 go?

2006-07-12 12:02:30 · 14 answers · asked by mandrake 1 in Science & Mathematics Mathematics

14 answers

each one only paid $8.33 times 3 and thats 25 plus the $2 on the table and the $3 that they have equals $30

2006-07-13 05:15:24 · answer #1 · answered by Yndy'91 3 · 5 0

At the end of the meal, each man has put in $9 towards the cost of the food: 3 x $9 = $27.
The tip was $2: $27 - $2 = $25.
The restaurant has collected $25.

Or to take it from the other direction:

The restaurant has $30 and gives $5 of that to the waiter to return to the men: $30 - $5 = $25.
The men leave a $2 tip: $5 - $2 = $3.
The men each end up with $1 each. Total it up: 3 x $1 + $2 + $25 = $30.

About the best the waiter could have done would be to give two men $1.67 and the last $1.66, which would be about as close to evenly dividing $5 he could have come to. The mistake in the instructions is when the riddle asks you to “add the $2 tip for the waiter” to the total the men spent. The tip would be subtracted, not added.

2006-07-12 12:24:56 · answer #2 · answered by NannyMcPhee 5 · 0 0

There is nothing to solve

They each paid $9 each. Three 9's does equal $27, but this $27 includes the tip, $25 for the meal and $2 for the tip.

2006-07-13 01:19:50 · answer #3 · answered by Anonymous · 0 0

it's not like that. As the waiter returned $1 for each of them, the remainder which is $27, consisted of the $25 paid for the bill and the $2 tip. so you must substract the 2 from the $27 and not add them.

2006-07-12 12:12:40 · answer #4 · answered by Turkleton 3 · 0 0

It's not $27 + $2, it's $27 - 2 for $25, the amount of the bill.

2006-07-12 12:06:50 · answer #5 · answered by Keith P 7 · 0 0

This has been posted here before...but the solution is that you are adding when you should be subtracting. The customers did NOT each pay $9, they each paid 1/3 of the dinner's cost of $25, or $8.33. The total of those is $25, plus $3 change, plus $2 tip = $30.

2006-07-12 12:06:03 · answer #6 · answered by -j. 7 · 0 0

Your calculation is incorrect. Each person paid more than $9. In fact they actually paid $9.33. 3 times $9.33 equals $28. So, $28 plus $2 that they left as tip equals $30.

What $1 missing?

2006-07-12 12:09:31 · answer #7 · answered by galactic_man_of_leisure 4 · 0 0

There is no missing dollar, You have included the two dollar tip twice.
the $27.00 paid included the tip and each recieved one dollar back giving a total of $30.00

2006-07-12 12:18:32 · answer #8 · answered by chubbiguy40 4 · 0 0

I agree with what the smart ones said.

2006-07-12 13:50:28 · answer #9 · answered by tsmith007 4 · 0 0

11 people have already answered, will i make a difference?

2006-07-12 21:43:22 · answer #10 · answered by avonlady 2 · 0 0

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