effect on total resistance of adding this third bulb?
a.Total resistance increases by one third
b.Total resistance triples
c.Total resistance decreases
d.Total resistance remains the same
2006-07-12 07:48:00 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Other - Science
"C" is the correct answer (Total resistance decreases)
The light bulbs can be thought of as three resistors connected in parallel, and the formula to find the total resistance is ==>
Total resistance = 1 divided by (1/r1 + 1/r2 + 1/r3)
If we say that each light bulb ("resistor") has a resistance of 5 ohms then Total resistance = 1.666666666...ohms
2006-07-12 08:07:52 · answer #1 · answered by Chug-a-Lug 7 · 3⤊ 1⤋
I am an electrical engineer and the answer is C, the total Resistance in parallel is smaller then the smallest parallel resistance. Use this formula.
1 / R = 1 / R1 + 1 / R2 + 1 / R3 +...
Hope this helps
If they are in series then the resistance adds up.
C is correct
2006-07-12 15:05:58 · answer #2 · answered by J D 2 · 0⤊ 0⤋
100 ohms, 200 ohms and 300 ohms, all in a circuit in parallel. The total (parallel) resistance would be 1 / (1/100 + 1/200 + 1/300) or about 54.555 ohms.
The correct answer is 'C'.
2006-07-12 15:16:43 · answer #3 · answered by galactic_man_of_leisure 4 · 0⤊ 0⤋
The resistance would only rise by a little so I would say
E. resistance increases by a small amount
2006-07-12 14:55:54 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I'm an electrical engineer who's taken multiple classes on this and a semester of physics where they hammered this into out brain. It's c. If you plug in numbers for it you can see it decreases
2006-07-12 15:08:31 · answer #5 · answered by sketch660 2 · 0⤊ 0⤋
d- if they are on a parallel cirrcuit the resistance does not change !! :) ??
2006-07-12 14:51:33 · answer #6 · answered by justwondering 3 · 0⤊ 0⤋
My son told me the answer to this is D. I'll check back to see if he's right.
:)
2006-07-12 15:04:26 · answer #7 · answered by Fiona70 2 · 0⤊ 0⤋