Is the resistor already under water and you want to measure how much heat it's generating?
If so, you need the amount of water - it's mass, but it's easy to convert from volume to mass since the density of water is 1 gram/milliliter. You need the mass of the resistor.
You need the temperature of the water once the resistor and the water have reached equilibrium.
You need the specific heat of the resistor. The specific heat of water is 4,186 Joules/(kg C). The specific heat of the resistor depends on the material - Silicon is 703 J/(kg C) and is a good estimate since most cheap resistors are imbedded in a silicon based ceramic.
By recording the temperature change of the water, you can determine approximately how much heat is generated by the resistor (approximate because the wires running to the resistor will generate some heat, as well).
The energy transferred between a material and its surroundings is: mc(delta T)
where m is the mass, c is the specific heat, and delta T is the change in temperature.
Using the mass of the water, its specific heat, and the change in the water temperature, you can determine how much energy was required for that temperature change.
The energy had to come from the resistor. Using the same equation, except with the amount of energy, the mass, and the specific heat now known, you solve for the change in temperature of the resistor.
2006-07-12 07:18:30
·
answer #1
·
answered by Bob G 6
·
0⤊
0⤋
properly, you may ought to style of look on the dimensions then, in the experience that they are very very small, then they're one million/8 watt resistors. in the experience that they are quite a lot an similar length in length because the letter I on your key board. they're one million/4 watt. a touch larger may be one million/2 watt
2016-12-10 08:31:11
·
answer #2
·
answered by ? 4
·
0⤊
0⤋
use latest thermometer,which can read by laser...use lasser to messure tht tempreture.
refer u can get ur answer here
http://www.novalynx.com/210-temperature.html
2006-07-12 06:42:13
·
answer #3
·
answered by Dj Div 5
·
0⤊
0⤋