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If the value of the coins is $17.70, then how many of each type does she have?

2006-07-12 05:39:53 · 10 answers · asked by Brandon ツ 3 in Science & Mathematics Mathematics

10 answers

Use this formula:

.25x + .10y = 17.70

x + y = 96

Using these formulas, you can arrive at your answer.

Your answer:

54 x .25 = 13.5
42 x .10 = 4.20

13.5 + 4.20 = 17.70

54 quarters, 42 dimes

2006-07-12 05:43:41 · answer #1 · answered by M 4 · 1 0

Given the information, you can make up a system of equations to solve.

Let Q = # of quarters and D = # of dimes.

Q + D = 96

25Q + 10D = 1770

Solve the first equation for D

D = 96 - Q

Substitute 96 - Q for D in the second equation

25Q + 10(96 - Q) = 1770
25Q + 960 - 10Q = 1770
25Q - 10Q = 1770 - 960
15Q = 810
Q = 54

Replace Q with 54 in the first equation

54 + D = 96
D = 42

Check using the secodn equation

25(54) + 10(42) = 1770
1350 + 420 = 1770
1770 = 1770

Note: no decimal point was used because equation 2 is stated in pennies.

2006-07-12 12:53:11 · answer #2 · answered by kindricko 7 · 0 0

54 quarters + 42 dimes = 96 coins = $17.70

2006-07-12 12:46:46 · answer #3 · answered by Just Some Guy 2 · 0 0

..25x + .10Y = $ 17.70

x + y = 96

Use the substitute Method

x + y = 96
- y = - y

Subtract y from both sides

x = 96 - y

.25(96-y) + 10 y = 17.70

Insert the x = 96 - y into the x value and multiply

24 - .25y + 10y = 17.70-24 -24

Subtract -24 from both sides

-.25y + .10y = -6.3
-.15y = -6.3

-0 .15y = -6.3

-0,15y/-0.15 = -6.3/-0.15

Divide both sides by -0.15

y = 42

First answer: Y = 42 Dimes

in the equation x + y = 96 Insert 42 in the x value

42 + y = 96
-42 -42

subtract -42 from both sides

y = 54
Second answer: y = 54 Quarters

the answer: she has 54 Quarters and 42 Dimes

2006-07-13 15:37:50 · answer #4 · answered by SAMUEL D 7 · 0 0

Lets say x quarters and y dimes, then we get

x+y = 96
x = 96-y
also 25x + 10y = 1770 (converting all into cents)

Substituting value of x in the second equation)
25*(96-y) + 10y = 1770
2400 - 25y + 10y = 1770
which gives 15y = 630

ie y = 42

putting y = 42 in the first equation we get x = 54

2006-07-12 12:45:21 · answer #5 · answered by SmartSpider 4 · 0 0

Kendra has 54 quarters and 42 dimes. Solved like this:

x = quarters
y = dimes

x + y = 96 (total coins)
.25x + .10y = 17.70

x + y = 96
x + .10y = 70.80 <-----I took the previous equation x 4

subtract the two above and you have the following:
.60y = 25.20
y = 42

with y=42, that means x = 54

2006-07-12 12:51:18 · answer #6 · answered by mcmurrayjamiefan 4 · 0 0

This is a two variable, two equation problem:

25x + 10y = 1770 (multiplied by 100 to avoid having decimals)
x + y = 96

Solve for either variable first. For example, multiply the second equation by 10 and then subtract it from the first:

25x - 10x + 10y - 10y = 1770 - 960
15x = 810
x = 54

then put that back into one of the equations to solve for y:

54 + y = 96, therefore y = 42

54 quarters is $13.50
42 dimes is $4.20

2006-07-12 12:45:40 · answer #7 · answered by Jeff A 3 · 0 0

54 quarters and 42 dimes

2006-07-12 12:45:22 · answer #8 · answered by Patrick H 2 · 0 0

42 dimes, 54 quarters

2006-07-12 12:44:55 · answer #9 · answered by Tim H 2 · 0 0

54 quarters and 42 dimes
duh, everyone was faster than me lol

2006-07-12 12:45:42 · answer #10 · answered by gnomes31 5 · 0 0

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