Use this formula:
.25x + .10y = 17.70
x + y = 96
Using these formulas, you can arrive at your answer.
Your answer:
54 x .25 = 13.5
42 x .10 = 4.20
13.5 + 4.20 = 17.70
54 quarters, 42 dimes
2006-07-12 05:43:41
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answer #1
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answered by M 4
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Given the information, you can make up a system of equations to solve.
Let Q = # of quarters and D = # of dimes.
Q + D = 96
25Q + 10D = 1770
Solve the first equation for D
D = 96 - Q
Substitute 96 - Q for D in the second equation
25Q + 10(96 - Q) = 1770
25Q + 960 - 10Q = 1770
25Q - 10Q = 1770 - 960
15Q = 810
Q = 54
Replace Q with 54 in the first equation
54 + D = 96
D = 42
Check using the secodn equation
25(54) + 10(42) = 1770
1350 + 420 = 1770
1770 = 1770
Note: no decimal point was used because equation 2 is stated in pennies.
2006-07-12 12:53:11
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answer #2
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answered by kindricko 7
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54 quarters + 42 dimes = 96 coins = $17.70
2006-07-12 12:46:46
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answer #3
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answered by Just Some Guy 2
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..25x + .10Y = $ 17.70
x + y = 96
Use the substitute Method
x + y = 96
- y = - y
Subtract y from both sides
x = 96 - y
.25(96-y) + 10 y = 17.70
Insert the x = 96 - y into the x value and multiply
24 - .25y + 10y = 17.70-24 -24
Subtract -24 from both sides
-.25y + .10y = -6.3
-.15y = -6.3
-0 .15y = -6.3
-0,15y/-0.15 = -6.3/-0.15
Divide both sides by -0.15
y = 42
First answer: Y = 42 Dimes
in the equation x + y = 96 Insert 42 in the x value
42 + y = 96
-42 -42
subtract -42 from both sides
y = 54
Second answer: y = 54 Quarters
the answer: she has 54 Quarters and 42 Dimes
2006-07-13 15:37:50
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answer #4
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answered by SAMUEL D 7
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Lets say x quarters and y dimes, then we get
x+y = 96
x = 96-y
also 25x + 10y = 1770 (converting all into cents)
Substituting value of x in the second equation)
25*(96-y) + 10y = 1770
2400 - 25y + 10y = 1770
which gives 15y = 630
ie y = 42
putting y = 42 in the first equation we get x = 54
2006-07-12 12:45:21
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answer #5
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answered by SmartSpider 4
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Kendra has 54 quarters and 42 dimes. Solved like this:
x = quarters
y = dimes
x + y = 96 (total coins)
.25x + .10y = 17.70
x + y = 96
x + .10y = 70.80 <-----I took the previous equation x 4
subtract the two above and you have the following:
.60y = 25.20
y = 42
with y=42, that means x = 54
2006-07-12 12:51:18
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answer #6
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answered by mcmurrayjamiefan 4
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This is a two variable, two equation problem:
25x + 10y = 1770 (multiplied by 100 to avoid having decimals)
x + y = 96
Solve for either variable first. For example, multiply the second equation by 10 and then subtract it from the first:
25x - 10x + 10y - 10y = 1770 - 960
15x = 810
x = 54
then put that back into one of the equations to solve for y:
54 + y = 96, therefore y = 42
54 quarters is $13.50
42 dimes is $4.20
2006-07-12 12:45:40
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answer #7
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answered by Jeff A 3
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54 quarters and 42 dimes
2006-07-12 12:45:22
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answer #8
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answered by Patrick H 2
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42 dimes, 54 quarters
2006-07-12 12:44:55
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answer #9
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answered by Tim H 2
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54 quarters and 42 dimes
duh, everyone was faster than me lol
2006-07-12 12:45:42
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answer #10
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answered by gnomes31 5
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