A customer goes to the bank and gets change for a $200 consisting of all $5 and $10 bills.?

Question

There are 26 bills in all. How many of each kind are there?

Answer 1

This kinds of question require the use of algebra, specifically simultaneous equations.

First let the number of 5 dollar bills be x and the number of 10 dollar bills be y.
Since there are 26 bills in total:
x + y = 26 (EQUATION 1)

The total value of the 5 dollar bills is $5x.
The total value of the 10 dollar bills is $10y
The total value of all the bills are $200
Therefore, 5x + 10y = 200 (EQUATION 2)

With equation 1 and 2 at hand you can easily solve for x and y using simultaneous equations.

From equation 1:
x + y = 26
x = 26 - y

substitute that into equation 2:
5(26 - y) + 10y = 200
5y = 70
y = 14
hence, x = 12

To check:
14 ten dollar bills (14 x 10 = $140) and 12 five dollar bills (12 x 5 = $60) gives you a total of $200 ($140 + $60 = $200)

I hope this is detailed enough. For question that require you to use simultaneous equations, remember to always get your equations first. Its smooth sailing from then on.

Have fun with math! It isn't your enemy. : )

Answer 2

14 10 dollar bills = $140
12 5 dollar bills = $60
26 bills total = $200

Answer 3

14 x $10= $140
12 x $5= $60

26 bills, $200

Answer 4

x+y = 26
5x+10y = 200

So x, the number of 5 dollar bills, is 12. And y, the number of 10 dollar bills, is 14.

12+14 = 26
5*12 + 10*14 = 200

Answer 5

Let us write this down

5X + 10Y = 200
X+Y = 26

To solve thsi

5X + 5Y = 130

On substraction we get
5Y = 70
Y = 14
X = 12
This is the answer
14 ten $ bilfs and 12 $5 bills

Answer 6

I am sure the customer is giving 2 $100bills and not 1 $200bill.

Answer 7

14 tens/12 fives

Answer 8

5a+10b=200
a+b=26
b=26-a
5a+260-10a=200
a=12 $5s
b=14 $10s

Answer 9

14 tens and12 fives

Answer 10

5x + 10y = 200
x + y = 26
etc ...