chemistry : balanced equation?

Question

how to balanced equation for the reaction of NaOH (aq)

with citric acid ( H3C6H5O7) ?

Answer 1

If you go here, http://en.wikipedia.org/wiki/Citric_acid, you will see the proper strutural formula and drawing of citric acid. You will also notice that it has 3 carboxylic acid groups (-COOH). Each of these groups can lose a proton to a base.

Since three acid groups are present, 3 moles of base is needed.

There is also an alcohol group (-OH). The -OH group is attached to a carbon that is in turn attached to 3 other carbon molecules. Therefore it is a tertiary alcohol and will form a stable carbocation if the (-OH) group loses its proton.

Since it has an -OH group forming a tertiary alcohol, it will react with 1 mole of base.

Hence 4 moles of base are nedeed.

HOOC-CH2-C(OH)COOH-CH2-COOH + 4NaOH =

NaOOC-CH2-C(ONa)COO(Na)-CH2-CO ONa + 4H2O

Answer 2

just acid base so you get H2O and the sodium salt of citric acid

Answer 3

lol im in yar 10 and have been doing that for the time of my chem & phys type. the instructor we had suggested it grow to be purely a count of trial and blunder. alsoo suggested some thing to do with commencing with the only that are closest at the same time

Answer 4

3NaOH + C6H8O7 ---> 3H2O + 3(Na+) (C6H5O7)3-

the (Na+) and (C6H5O7)3- are charged species that are ionic in nature

Answer 5

........................OH
........................|
HOOC-CH2-C-CH2-COOH + 3NaOH(aq) -------->
........................|
........................COOH
(citric acid)

..........................OH
...........................|
NaOOC-CH2-C-CH2-COONa + 3H2O
...........................|
.........................COONa
(trisodium citrate)

And ignore the dots they are only for spacing purposes.