Eleven chairs are numbers 1-11. Four girls and 7 boys sit on these chairs at random. What is the probability that chair 5 is occupied by a boy?
2006-07-12 04:46:03 · 4 answers · asked by socola20 1 in Science & Mathematics ➔ Mathematics
7/11= .63
order doesnt matter, as there are no other conditions. the probability of being in one seat is the same as all others.
2006-07-12 04:49:47 · answer #1 · answered by jasonalwaysready 4 · 0⤊ 0⤋
about 63% sure that it'll be a boy. If there were 12 chairs and there were 4 girls and 8 boys then the odds would be 2/3rds in favor of boys or 66%. So its a little less than 66%.
2006-07-12 12:00:43 · answer #2 · answered by vmmhg 4 · 0⤊ 0⤋
7/11, the same for each of the chairs.
2006-07-12 11:49:52 · answer #3 · answered by Paul P 5 · 0⤊ 0⤋
7/11 or 0.636363
2006-07-12 12:02:12 · answer #4 · answered by jimbob 6 · 0⤊ 0⤋