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3 answers

it is all relative to a few different factors:
A) Amount of force that the goaltender is capable of
B) Angle of trajectory
C) Wind Resistance

2006-07-12 01:58:17 · answer #1 · answered by bigred8882 4 · 0 0

i studied the laws of projection of objects

to answer that question u must know alot of variables:
a) the force of the goalkeeper's kick on the ball & don't forget the resistance of the air (they r not too important in the equation)
b) the angle between the tangent to the trajectory of the ball & x-axis (at the point of impact between the leg of goalkeeper & the ball)
c) the velocity of the ball
d) we must also put the gravity in the equation becouse it affect the trajectory that the ball take in its way

& by applying this equation of projection we can find the hight:
Y(max) = [ (v^2)*{(sin^2)x} ] / 2g

where:
Y(max) is the maximum vertical hight
v is the velocity of the ball at the point of impact between it & the leg of the goalkeeper
x is the angle between the tangent to the trajectory of the ball & x-axis (at the point of impact & the leg of the goal keeper)
g is the gravity = 9.8 m/(s^2)

i hope u got ur point from my explanation

2006-07-16 03:06:10 · answer #2 · answered by Kevin 5 · 0 0

The body is considered at two instants in time: one "initial" point and one "current". Often, problems in kinematics deal with more than two instants, and several applications of the equations are required.

v_f = v_i + a Delta t \,
d = 1/2(v_i + v_f) Delta t
d = v_i Delta t + 1/2} a Delta t^2
v_f^2 = v_i^2 + 2ad,
d = v_f\Delta t - \begin{matrix} \frac{1}{2} \end{matrix} a\Delta t^2

where...

v_i, is the body's initial speed



and its current state is described by:
d \,, the distance travelled from initial state
v_f \,, the current speed
\Delta t \,, the time between the initial and current states
a is the constant acceleration, or in the case of bodies moving under the influence of gravity, g.

Note that each of the equations contains four of the five variables. When using the above formulae, it is sufficient to know three out of the five variables to calculate remaining two.

2006-07-12 02:19:51 · answer #3 · answered by (¯`·.¸¸.·*«βѯmïlîäñø*.¸¸.·´¯) 1 · 0 0

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