Can someone please help me with this? (I don't understand it) Thank you soo much!!?

Question

1. 5(2x - 7) > 10

2. 3(3w+1) > or = to 48

3. 5(5z - 3 ) < or + to 60

4. 40 < or = to -6(5r - 7)

5. 3x + 1 < x + 5

6. 3 - 2x > or = 0

Answer 1

Work them just like any equation. Do your brackets (), multiply & divide first. Then your + & -. The balance your equation and reduce to your variable (x).
1. 10x-35>10
10x>45
x>4.5

Answer 2

1. First distribute the number outside the parentheses onto both terms inside like so.
10x-35 > 10
add 35 to both sides
10x>45
divide 10 by both sides
x>4.5

2. Similarly 3(3w+1) > or = to 48
9w+9>or = to 48
subtract 9 from both sides
9w>or=to39
divide 9 on both sides
w>or=to 13/3 or 4.3333333333

3. same logic as 1 and 2

4. same logic with a negative sign added in
40 < or = to -30r+42 (distribute)
-2 < or = to -30r (subtract 42)
1/15 > or = to r (divide -30, flip sign)

5. 3x + 1 < x + 5
Goal is to isolate x. Start with 1 and 5. Get them both on one side.
3x < x+4 (subtract 1)
3x-x < +4 (subtract x)
2x < +4 (combine like terms)
x < 2 (divide by 2)

6. same logic as 5

Answer 3

Don't let the < and > confuse you...solve it as though they are =.

1) 5(2x-7) > 10
10x-35>10
10x-35+35>10+35
10x>45
10x/10>45/10
x>4.5

you can do 2-4 and 6 the same way, but I'll show you 5.

5) 3x+1 3x+1-1 3x 3x-x 2x<4
2x/2<4/2
x<2

Hope this helps!

Answer 4

Inequalities are fun! Just don't forget to flip the inequality sign if you divide or multiply both sides by a negative number. Pay more attention in class and ask your teacher/tutor lots of questions, they should be glad to help.