y - 6 = (1/3)(x-(-3))
y - 6 = (1/3)(x+3) point-slope form
y - 6 = (1/3)x + 1
y = (1/3)x + 7 slope-intercept form
-(1/3)x + y = 7
Multiply everything by -3
x - 3y = -21 General form
2006-07-11 15:09:22
·
answer #1
·
answered by MsMath 7
·
2⤊
0⤋
y=6+(x+3)/3
=x/3 +7
2006-07-11 15:05:13
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
the line that passes through (-3,6) and has a slope of 1/3.
so line: y=kx+b
k=1/3
y=1/3x+b
6=-1+b
b=7
line: y=1/3x+7
2006-07-11 16:29:10
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
y = mx + b; substitute
6 = (1/3)(-3) + b
6 = -1 + b
7 = b
The line is y = (1/3)x + 7
2006-07-11 18:57:52
·
answer #4
·
answered by jimbob 6
·
0⤊
0⤋
x+3=(y-6)/3
3x-y+15=0
2006-07-11 15:12:27
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
(x1,y1)= (-3,6)
(y-y1) = m(x-x1)
y-6=1/3(x+3)
3y-18=x+3
3y-x=21
2006-07-11 18:16:02
·
answer #6
·
answered by budweiser 2
·
0⤊
0⤋
y=1/3x+7
I took that stuff last year. thanks for keeping me sharp.
2006-07-11 15:06:16
·
answer #7
·
answered by mbezlr 3
·
0⤊
0⤋