Write the equation of the line that passes through point (0, -8) with a slope of 7/10.?

Question

Does anyone know how to solve this?

Answer 1

we know that m (slope) = 7/10
the line pass through point (0,-8) where x=0 and y=-8
put this into general equation y = mx + c
-8 = 7/10 (0) + c
c = -8

so the line equation will be
y = 7/10 x - 8
or we can write it in another way
10y = 7x - 8
7x - 10y - 8 = 0

Answer 2

You need a graph with a cartesian coordinate plane, or a big cross that divides a grid into 4 equal parts. The horizontal line is x, vertical is y. For x, everything right of the vertical y is positive, and left of it is negative. For y, everything up from the horizontal x is positive, and down is negative. Where the two lines meet is 0/0. When a coordinate is given, it's x first, then y. For your example, the slope is 7/10. This means that when x is 7, y is 10. This can be expressed as

7x = 10y

To simplify, solve for one variable, it doesn't matter which but in this case y is easier.

7x/10 = y
OR
y = .7x

In order for this slope, y = .7x, to pass through 0/-8, look at the graph. Find 0/-8 by sliding along the y axis (vertical) until you find -8. The line must pass through this point. Your equation becomes

y = .7x - 8 <--- answer to question


To check, enter the coordinate for x

y = .7(0) - 8
When solved
y = -8

Hopefully not too long winded for you, have fun avoiding homework like I do.

Answer 3

There is a point-slope form for the equation of a line. It says
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is the point.

So you have a slope of 7/10 with the point (0, -8). That means

y - (-8) = 7/10(x - 0)

y + 8 = 7x/10

Now we can go several directions. If you want this in slope-intercept form, subtract 8 from both sides

y = 7x/10 - 8

If you want it in standard form, clear the fraction and get x & y on the same side

10y = 7x - 80

7x - 10y = 80

The point-slope form of the line is where you start--since you have a point and a slope.

Answer 4

well, using slope-intercept form, you have y=mx+b where m is the slope and b is the y-coordinate of the y-intercept. So m=7/10 and b=-8 (since the point is 0,-8)

Then the equation is y=7/10x-8

Answer 5

Use the point-slope formula: y = mx + b

y - y1= m(x - x1) won't work here because you are only given one x and one y.

So, x = 0 and y = -8. and m = 7/10

-8 = 7/10(0) + b Solve for b.
-8 = 0 + b. b = 8

So, y = 7/10x + 8 is your answer.

Answer 6

living house artwork for weekend? evaluate: 2a^2 even as a = 5. 2a^2 ; a = 5 = 2(5*5) = 50 8.) locate the slope of a line that passes by potential of the criteria (2,-3) and (-4,5). m = 5-(-3) / 2-(-4) = 8/6 = 4/3

Answer 7

To write an equation you need to know slope and y-intercept; you have been given both.

slope = 7/10
y-intercept = -8

y = (7/10)x - 8

Answer 8

I think the answer might be y=7/10x - 8 if it needs to be in slope-intercept form. But I'm not 100% sure. And that's seven-tenths x not seven over 10x.

Answer 9

Using the point-slope formula [y-y1=m(x-x1)], where m=slope and (x1,y1) is the given point, your equation in standard form becomes 7x-10y=80.

Answer 10

[y-(y1)]/[x-(x1)]=slope, using this equation

[y-(-8)]/[x-(0)]=7/10 ------------> y+8=7*x/10

y=0.7*x-8. QED