Can anyone try to help?
2006-07-11 14:25:47 · 8 answers · asked by NewYorker32 1 in Science & Mathematics ➔ Mathematics
the first integer, we will call n. The second is 2 greater (must be odd), so it is n+2
Thus 5n=12+3(n+2) Now, simplify and solve
5n=12+3n+6
5n=18+3n
2n=18
n=9
So one is 9 and the other is 11
2006-07-11 14:31:24 · answer #1 · answered by Amber E 5 · 3⤊ 3⤋
9 and 11
Ur 2 odd intergers are unknown so lets called them x and x+2 (it is plus 2 because it is consecutive and its odd like 1 and 3 or 5 and 7 which are odd and consecutive and are 2 numbers apart)
five times the first interger is
5x
and 12 more than three times the second is
3(x+2)+12
so ur problem is 5x=3(x+2)+12
5x=3x+6+12
5x=3x+18
2x=18
and so x =9 (ur 1st interger) and the second one is x+2 (x=9) so plug in for x, u get x+2 is the same as 9+2 which is 11.
2006-07-11 21:38:21 · answer #2 · answered by Will 2 · 0⤊ 0⤋
Call the first integer n. Then the second one is n+ 2. They can be related by this equation:
5n = 12 + 3(n + 2)
5n = 12 + 3n + 6
2n = 18
n = 9
So the two numbers are 9 and 11.
To check: 5*9 = 45 which is 12 more than 33 which is 3*11.
2006-07-11 21:29:07 · answer #3 · answered by mathsmart 4 · 0⤊ 0⤋
Let x & x+2 are the odd integers,
Now as per the condition,
5x = 3(x+2)+12.
Solving the above Equation we have x=9.
So the integers are:9 & 11.
2006-07-11 21:30:48 · answer #4 · answered by Pramod 2 · 0⤊ 0⤋
x = first integer
x + 2 = second integer
5x = 3(x + 2) +12
5x = 3x + 6 + 12
5x = 3x + 18
2x = 18
x = 9
The numbers are 9 and 11
2006-07-12 02:01:38 · answer #5 · answered by jimbob 6 · 0⤊ 0⤋
5x -12 = 3(x +2)
2006-07-11 21:29:13 · answer #6 · answered by bette 5 · 0⤊ 0⤋
The answers so far are incomplete.
9,11
or
3,1
You didnt say that the first one was the smaller one or the second the larger.
2006-07-11 22:37:50 · answer #7 · answered by Scott R 6 · 0⤊ 0⤋
why are we doing your math homework for you?
2006-07-11 21:36:27 · answer #8 · answered by scslmd 2 · 0⤊ 0⤋