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24 answers

50.

2006-07-11 11:25:21 · answer #1 · answered by kimmyisahotbabe 5 · 1 0

Perimeter and not area?

It depends on:
A) the shape of the patio - i'm guessing that when you say a "8ft sq patio" you mean a patio in the shape of a square, with each side 8 feet long, and not a patio whose total area is 8 square feet, but with unknown shape. If the area is 8 square feet, and we don't know the shape of the patio, then the perimeter could be nearly anything.

B) are the bricks going just inside the perimeter or just outside the perimeter - it makes a difference as the bricks have their own area and can't overlap each other. If the bricks form the perimeter and are part of the patio.

C) how the bricks are arranged? do you want it so that most bricks use their long side against the perimeter? or their short side? or some sort of decorative pattern alternating long side and short side.

Here's how i would do it, using the least number of bricks, assuming a square of side 8 feet.
Side 1: 8 feet long = 96 inches. lay bricks the long way along the edge, so that the bricks are inside the patio square. 96 inches / 8 inch bricks = 12 bricks.
Side 3 (the side opposite side 1) - same thing - 12 bricks.
Sides 2 and 4: since each end of sides 2 and 4 is already covered by 4 inches of the bricks that are along sides 1 and 3, there is only 96 inches - 4 inches (one end) - 4 inches (other end) = 88 inches left to cover. 11 bricks each side.

total bricks used = 12 + 12 + 11 + 11 = 46 bricks.

2006-07-11 11:41:00 · answer #2 · answered by jawajames 5 · 0 0

It depends on how you are going to position the bricks on the perimeter. Are you going to have to have the 8 in side or the 4 in side line the patio?

I'll work it out both ways.

So, we have a square patio that has four 8 ft sides. That means the perimeter is 32 ft (8 + 8 + 8 + 8 = 32).

Let's convert that to inches: 32 x 12 = 384 in.

If the 4 in side is going to line the patio, then you'll need at least 96 bricks: First, divide 384 by 4, which gives you 96. If you wants bricks to cover the corners, add 4 more. (Draw a diagram and you'll see what I mean).

If the 8 in side is going to cover the patio, then you'll need at lest 48: Divide 384 by 8, which gives you 48. I'd get about 52 depending on how you arrange the bricks.

2006-07-11 11:48:41 · answer #3 · answered by student2000 2 · 0 0

Brian, as you can see from the variety of answers you got, you REALLY need to think about how you phrase your ?. You DID say perimeter, not area, and they ARE 2 entirely different things. The phrase "cover the perimeter" is about as ambiguous as it gets, since a perimeter is a line and the bricks have an area. You DID say "8 ft sq", which is distinctly different than "8 sq ft", which means the perimeter is precisely 4*8 = 32 ft, but then you didnt say how the bricks were aligned along the perimeter. If the bricks were lined up diagonally on the preimeter it would take about 42.93 of them to "cover" it. 32*12 over sqrt(8^2+4^2)

2006-07-11 12:15:20 · answer #4 · answered by Steve 7 · 0 0

Two opposite sides need 12 bricks each (8 ft = 96 in, 96 divided by 8 = 12), that's 24 bricks. The remaining sides have only 88 inches to cover because the two bricks at each corner already cover 8 inches (2 x the width of 4 in.) You will need 11 bricks to cover each of the remaining 2 sides, that's 22 more bricks. 24 + 22= 46 bricks.

2006-07-11 11:40:44 · answer #5 · answered by adjjb 2 · 0 0

The patio is 8 feet on a side, so that is 96 inches. When the bricks are put the long way, you will fit 96/8 = 12 on a side. When they are put the short way, you will fit 96/4 = 24 on a side. If you lay them the long way along the length and the short way along the width, you will have 12x24 = 288 bricks.

Another way to figure it is that the total area of the patio is 96^2 = 9216 square inches. The area of a brick is 8x4= 32 square inches. So the number of bricks that will fit is 9216/32 = 288.

2006-07-11 11:27:29 · answer #6 · answered by mathsmart 4 · 0 0

46

8 ft = 96 inches
u will need 12 bricks for 2 of the sides
for the other 2 u would need 12 but the other bricks are 4 inches thick so 8 inches r already covered so u only need 11
12+12+11+11=46

2006-07-11 11:51:42 · answer #7 · answered by CaliBeachBabe 2 · 0 0

I love the variety of answers!
Ian was close but if you are putting the bricks ON a concrete patio and not AROUND the outside you would need 4 fewer bricks.
That is, if you were starting a wall and not planting the bricks in the dirt around the patio.
12 + 12 + 11 + 11 or 46

2006-07-11 11:45:21 · answer #8 · answered by a simple man 6 · 0 0

50 total.

The patio is 8ft sq, which means each side is 96 in long. Laying bricks along two opposite sides, you'll need 12 bricks each, or 24 total. For the remaining two sides, the patio itself is still 96 in long. However, you now have two rows of bricks, which are 4 in wide for another 8 in on either side. Therefore, for these two sides, you need 13 bricks, or 26 total. Then, the total number of bricks required is 50.

2006-07-11 11:30:06 · answer #9 · answered by Ian M 5 · 0 0

648. The width (making use of the 4" of brick) ought to take 3 in preserving with each and every foot. 3x6 equals 18. The length ought to take 3 bricks for 2 ft of distance. 24 divided by 2 is is 12. Then 12 x 3 is 36. 36x18 is 648.

2016-10-14 09:08:41 · answer #10 · answered by ? 4 · 0 0

Ian's answer showed correct thinking. However, if we allow that the boundary has zero width, then if we lay the first two rows so that the sides of the bricks facing "outward" are right at the boundary, then those two rows also cover four inches of the other boundary sections, and the remainder of those sections can be covered by eleven bricks on each section. Total bricks used: 46

2006-07-11 11:50:50 · answer #11 · answered by TP 1 · 0 0

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