How high is the building?
I suggest you go to the top floor with a stop watch, open the elevator doors and jump.
P.S. Don't forget to stop the watch when you land.
2006-07-11 09:00:13
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answer #1
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answered by Anonymous
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Normal freefall hits terminal velocity in about 10 seconds (120mph in a stable body position) taking about 1000 ft.
Problem with your plan is that this will take a c1000 ft lift shaft in a vacuum. If you do manage to find a tall empty shaft in a vacuum though your terminal velocity will be faster due to the lack of wind resistance.
Don't try this at home kids.
=8-)
2006-07-13 12:21:16
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answer #2
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answered by Anonymous
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Terminal velocity is reached because of wind resistance. Terminal velocity is when the force of wind resistance is equal to the force of gravity. You won't be at true free fall unless there is no air in the elevator shaft, In that case there would be no terminal velocity. As it is most buildings I know of are not tall enough to reach terminal velocity or even have the force of wind resistance to be very large at all.
2006-07-11 08:58:39
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answer #3
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answered by georgephysics13 3
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All the way to the bottom. You didn't say the number of floors.
5 or 105?
It can't be done. there has to be terminal velocity and wind resistance or there would be no reality. Without reality there's no elevator shaft and no freefall.
Fantasy and reality don't mix.
2006-07-11 08:59:53
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answer #4
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answered by Anonymous
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Indefinitely. In the absence of any resistance, freefall will go on until the core is reached, at which point it will turn into a deceleration and, ultimately, an oscillation between your starting position and the diametrically opposing position on the other side of Earth.
Unless of course, you assume that there is a bottom to hit. In which case, acceleration stops once it is reached. And quite suddenly, I might add.
2006-07-11 08:59:36
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answer #5
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answered by stellarfirefly 3
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You might want to mention the height of the building. It's a minor variable to the equation.
2006-07-11 08:58:37
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answer #6
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answered by justwebbrowsing 3
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since is without terminal velocity
a=(v-u)/t , v=0, u=0,t=?, a=10
10=(0-0)/t
10t=0
t=o/10
t=0
therefore, it will take 0 second
2006-07-11 09:16:57
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answer #7
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answered by Anonymous
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