Dude, I answered your question above, and then I noticed all of these other ones. Do your own damn number theory homework.
2006-07-11 09:32:10
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answer #1
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answered by mathbear77 2
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Order or 3 (mod 14)= LCM( order of 3 (mod 2), order of 3 (mod 7))
3^n=1 (mod 14) ==>>
3*n=1 (mod 2) and 3^n=1 (mod 7)
3^n=1^n=1 (mod 2) order of 3 (mod 2) is 1
3^2=9=2 (mod 7)
3^3=3•2=6=-1 (mod 7)
thus (3^3)^2=(-1)^2=1 (mod 7) thus the order of 3 (mod 7) is 6
Thus the order of 3 (mod 14) is LCM(1,6) = 6
Knowing that 3^6=1 (mod 14) you can check that this is the lowest such n in the following way. If a is the order of 3 (mod 14) then a|6, thus a=1,2,3, or 6 3â 1, 3^2=9â 1, and 3^3=27=-1â 1 (mod 14), thus 6 IS the smallest such n.
2006-07-11 15:17:23
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answer #2
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answered by Eulercrosser 4
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