1-bromo-pentane(BrCH2CH2CH2CH2CH3) + Sodium Ethoxide(CH3CH2ONa) is treated in Ethanol. Provide the name and structure of the major product formed from this reaction, and state what type of a mechanism the major product is.
2006-07-11 07:54:09 · 4 answers · asked by wsimms20 1 in Science & Mathematics ➔ Chemistry
the most logical is CH3CH2OH + NABr + PENTAN
2006-07-11 09:03:48 · answer #1 · answered by pussura 3 · 0⤊ 2⤋
shashank.chintalagiri is correct about the name:
CH3CH2CH2CH2CH2OCH2CH3, it's an ether, common name ethyl pentyl ether, IUPAC name ethoxypentane.
I'm not sure what he meant by "free radical mechanism", but here's what I think:
Ethoxides are much stronger nucleophilie than bromide, so bromium ions are better LG than ethoxides. The reaction will follow SN2 mechanism. New bond forms between #1 carbon and ethoxide, while the bond between the carbon and bromium breaks. No carbocation formed during the process [because the reactant is 1-bormopentane, so ONLY SN2 mechanism is possible].
2006-07-11 09:17:08 · answer #2 · answered by nickyTheKnight 3 · 0⤊ 1⤋
Pentoxy ethane
CH3CH2CH2CH2CH2-O-CH2CH3
2016-09-20 06:30:04 · answer #3 · answered by Sk8ergirl USA 2 · 1⤊ 0⤋
i think the correct answer is CH3-CH2-O-CH2-CH2-CH2-CH2-CH3 , or ethoxy pentane , aka ethly pentyl ether .
its a free radical mechanism.
2006-07-11 08:00:09 · answer #4 · answered by shashank.chintalagiri 2 · 1⤊ 0⤋