3x + 12 = 33
3x = 21
x = 7.
2006-07-11 07:29:25
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answer #1
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answered by nicegal 3
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7
2006-07-11 07:30:09
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answer #2
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answered by Anonymous
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7
2006-07-11 07:29:48
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answer #3
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answered by marieandlucaspape 3
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This is called trial and error.
x=1 15=33 wrong
x=2 18=33 wrong
x=3 21=33 wrong
x=4 24=33 wrong
x=5 27=33 wrong
x=6 30=33 wrong
x=7 33=33 right!
2006-07-11 07:44:05
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answer #4
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answered by fresh2 4
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x=7
2006-07-11 08:12:31
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answer #5
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answered by Anonymous
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x=7
2006-07-11 07:38:00
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answer #6
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answered by clam 1
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x=7
2006-07-11 07:29:34
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answer #7
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answered by Anonymous
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Divide 33 by 3 then subtract 4.
2006-07-11 07:29:36
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answer #8
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answered by wannabebeachbum 3
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3x?=33
3x11=33
4+?=11
4+7=11
so the value of x is 7
4+7x3=33
2006-07-11 07:54:51
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answer #9
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answered by Givingitthought 2
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3x +12=33
subtract 12 from both sides to eliminate 12
3x=21
Divide each side by 3
your answer is x=7
2006-07-11 07:40:12
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answer #10
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answered by emdorsheimer 1
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3(x+4)=33 becomes 3x+12=33
3x= 33-12
3x=21
x=21/3
x=7
2006-07-11 07:30:56
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answer #11
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answered by CHos3n 5
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