Three workers pick 66 bushels of apples in a day. One of the workers is three times more productive than the second worker and twice as productive as the third worker. How many bushels did the second most productive worker pick?
2006-07-11 06:34:56 · 4 answers · asked by jsha2424 3 in Education & Reference ➔ Homework Help
first most productive=a
second most productive=c
third most productive=b
a+b+c=66
a=3b
a=2c
3b=2c
b=2c/3
2c+2c/3+c=66
we multiply and divide with 3
6c+2c+3c=198
11c=198
c=198/11
c=18
b=2*18/3=12
a=3b=3*12
a=36
2006-07-11 09:12:06 · answer #1 · answered by dianna30eur 1 · 0⤊ 1⤋
Suppose third worker picks bushels = a
Then first worker picks 2a
And second one picks 2a/3
So a + 2a + 2a/3 = 66
3a + 2a/3 = 66
11a/3 = 66
a = 18
So third picks 18
first picks 36
and second picks 12
So the second most productive worker is the one who picked 18 bushels.
2006-07-11 13:50:56 · answer #2 · answered by nicegal 3 · 0⤊ 0⤋
The second worker picked 18 apples.
First worker picked 36 apples.
The third worker picked 12 apples.
2006-07-11 13:51:50 · answer #3 · answered by Newman 3 · 0⤊ 0⤋
18 bushels
most-36
second most -18
third most-12
2006-07-11 13:52:51 · answer #4 · answered by justicejamie888 3 · 0⤊ 0⤋